Microsoft 070-461復習テキスト「Querying Microsoft SQL Server 2012/2014」認証試験に合格することが簡単ではなくて、Microsoft 070-461復習テキスト証明書は君にとってはIT業界に入るの一つの手づるになるかもしれません。しかし必ずしも大量の時間とエネルギーで復習しなくて、弊社が丹精にできあがった問題集を使って、試験なんて問題ではありません。 NewValidDumpsのMicrosoftの070-461復習テキスト試験トレーニング資料はよい選択で、あなたが首尾よく試験に合格することを助けられます。これも成功へのショートカットです。 今の社会の中で、ネット上で訓練は普及して、弊社は試験問題集を提供する多くのネットの一つでございます。

MCTS 070-461 私の夢は最高のIT専門家になることです。

MCTS 070-461復習テキスト - Querying Microsoft SQL Server 2012/2014 私たちはお客様のための利益を求めるのを追求します。 最近、Microsoftの070-461 合格内容試験は非常に人気のある認定試験です。あなたもこの試験の認定資格を取得したいのですか。

しかし、Microsoftの070-461復習テキスト認定試験に合格するという夢は、NewValidDumpsに対して、絶対に掴められます。NewValidDumpsは親切なサービスで、Microsoftの070-461復習テキスト問題集が質の良くて、Microsoftの070-461復習テキスト認定試験に合格する率も１００パッセントになっています。NewValidDumpsを選ぶなら、私たちは君の認定試験に合格するのを保証します。

Microsoft 070-461復習テキスト - 弊社の開発したソフトは非常に全面的です。

NewValidDumpsのMicrosoftの070-461復習テキスト試験トレーニング資料は豊富な経験を持っているIT専門家が研究したものです。君がMicrosoftの070-461復習テキスト問題集を購入したら、私たちは一年間で無料更新サービスを提供することができます。もしMicrosoftの070-461復習テキスト問題集は問題があれば、或いは試験に不合格になる場合は、全額返金することを保証いたします。

弊社のホームページでソフトのデモをダウンロードして利用してみます。我々の商品はあなたの認可を得られると希望します。

070-461 PDF DEMO:

QUESTION NO: 1
You have an XML schema collection named Sales.InvoiceSchema.
You need to declare a variable of the XML type named invoice. The solution must ensure that the invoice is validated by using Sales.InvoiceSchema.
The solution must ensure that the invoice variable is validated by using Sales.InvoiceSchema schema.
Provide the correct code in the answer area.
Answer:
DECLARE @invoice XML(Sales.InvoiceSchema)

QUESTION NO: 2
You are the administrator for a heavily-used OLTP Microsoft SQL Server database.
You are troubleshooting performance issues seen when using stored procedures in the database. The database stores millions of orders across thousands of customers. Some of the customers have large numbers of orders, while others have only one order. You update the statistics and perform defragmentation of all tables and indexes, but two stored procedures still have issues when accessing data.
p_GetCustomer accepts @companyID as a parameter. From the results of profiling, you know that 90 percent of the calls use the @companyid value of 5, while the other 10 percent of calls are evenly distributed across another 10000 values. While viewing the execution plan, you discover that a non- clustered index seek is used.
p_GetShipDate accepts @orderID as a parameter and returns the ship date for that order. You discover that the execution plan is performing a scan on a non-clustered index that has orderID as the index key.
You need to add appropriate query hints to each stored procedure to improve the performance.
What should you do? To answer, drag the appropriate procedures to the correct hints. Each procedure may be used once, more than once, or not at all. You may need to drag the split bar between panes or scroll to view content.
Answer:
Explanation:
Box 1: Optimize FOR..
OPTIMIZE FOR ( @variable_name { UNKNOWN | = literal_constant } [ , ...n ] ) Instructs the query optimizer to use a particular value for a local variable when the query is compiled and optimized. The value is used only during query optimization, and not during query execution.
Box 2: FORCESEEK
FORCESEEK [ (index_value(index_column_name [ ,... n ] )) ]
Specifies that the query optimizer use only an index seek operation as the access path to the data in the table or view.
References:
https://docs.microsoft.com/en-us/sql/t-sql/queries/hints-transact-sql-query?view=sql-server-2017
https://docs.microsoft.com/en-us/sql/t-sql/queries/hints-transact-sql-table?view=sql-server-2017

QUESTION NO: 3
You administer a Microsoft SQL Server 2012 database named ContosoDb. Tables are defined as shown in the exhibit. (Click the Exhibit button.)
You need to display rows from the Orders table for the Customers row having the CustomerId value set to 1 in the following XML format:
<row OrderId="1" OrderDate="2000-01-01T00:00:00" Amount="3400.00" Name="Customer A"
Country="Australia" />
<row OrderId="2" OrderDate="2001-01-01T00:00:00" Amount="4300.00" Name="Customer A"
Country="Australia" /> Which Transact-SQL query should you use?
A. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML RAW
B. SELECT Name AS 'Customers/Name', Country AS 'Customers/Country', OrderId, OrderDate,
Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId = 1 FOR XML PATH ('Customers')
C. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId - Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML AUTO, ELEMENTS
D. SELECT Name, Country, OrderId, OrderDate, Amount
FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML AUTO, ELEMENTS
E. SELECT Name, Country, OrderId, OrderDate, Amount
FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML AUTO
F. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML AUTO
G. SELECT Name AS '@Name', Country AS '@Country', OrderId, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML PATH ('Customers')
H. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML RAW, ELEMENTS
Answer: A

QUESTION NO: 4
Your database contains a table named Purchases. The table includes a DATETIME column named PurchaseTime that stores the date and time each purchase is made. There is a non-clustered index on the PurchaseTime column.
The business team wants a report that displays the total number of purchases made on the current day.
You need to write a query that will return the correct results in the most efficient manner.
Which Transact-SQL query should you use?
A. SELECT COUNT(*)
FROM Purchases
WHERE PurchaseTime = GETDATE()
B. SELECT COUNT(*)
FROM Purchases
WHERE PurchaseTime >= CONVERT(DATE, GETDATE())
AND PurchaseTime < DATEADD(DAY, 1, CONVERT(DATE, GETDATE()))
C. SELECT COUNT(*)
FROM Purchases
WHERE CONVERT(VARCHAR, PurchaseTime, 112) = CONVERT(VARCHAR, GETDATE(), 112)
D. SELECT COUNT(*)
FROM Purchases
WHERE PurchaseTime = CONVERT(DATE, GETDATE())
Answer: B
Explanation:
Two answers will return the correct results (the "WHERE CONVERT..." and "WHERE ... AND ... " answers).
The correct answer for Microsoft would be the answer that is most "efficient". Anybody have a clue as to which is most efficient? In the execution plan, the one that I've selected as the correct answer is the query with the shortest duration. Also, the query answer with "WHERE CONVERT..." threw warnings in the execution plan...something about affecting CardinalityEstimate and SeekPlan.
I also found this article, which leads me to believe that I have the correct answer:
http://technet.microsoft.com/en-us/library/ms181034.aspx

QUESTION NO: 5
You have a database that contains the tables shown in the exhibit. (Click the Exhibit button.)
You need to create a view named uv_CustomerFullName to meet the following requirements:
* The code must NOT include object delimiters.
* The view must be created in the Sales schema.
* Columns must only be referenced by using one-part names.
* The view must return the first name and the last name of all customers.
* The view must prevent the underlying structure of the customer table from being changed.
* The view must be able to resolve all referenced objects, regardless of the user's default schema.
Which code segment should you use?
To answer, type the correct code in the answer area.
A. CREATE VIEW Sales.uv_CustomerFullName
WITH SCHEMABINDING
AS
SELECT FirstName, LastName
B. CREATE VIEW Sales.uv_CustomerFullName
WITH SCHEMABINDING
AS
SELECT FirstName, LastName
FROM Sales.Customers
Answer: B
Reference:
http://msdn.microsoft.com/en-us/library/ms187956.aspx

Salesforce ANC-301 - すべてのことの目的はあなたに安心に試験に準備さされるということです。 MicrosoftのSalesforce Salesforce-Data-Cloud試験に参加するのを決めるとき、あなたは強い心を持っているのを証明します。 我々のMicrosoftのOracle 1z0-076ソフトを利用してお客様の高通過率及び我々の技術の高いチームで、我々は自信を持って我々NewValidDumpsは専門的なのだと言えます。 我々Cisco 300-425J資料はIT認定試験の改革に準じて更新していますから、お客様は改革での問題変更に心配するは全然ありません。 CompTIA FC0-U61J - すべては豊富な内容があって各自のメリットを持っています。

Updated: May 28, 2022