また、NewValidDumpsのMicrosoftの070-461日本語版試験トレーニング資料が信頼できるのは多くの受験生に証明されたものです。NewValidDumpsのMicrosoftの070-461日本語版試験トレーニング資料を利用したらきっと成功できますから、NewValidDumpsを選ばない理由はないです。試験の準備をするためにNewValidDumpsのMicrosoftの070-461日本語版試験トレーニング資料を買うのは冒険的行為と思ったとしたら、あなたの人生の全てが冒険なことになります。 NewValidDumps提供した商品の品質はとても良くて、しかも更新のスピードももっともはやくて、もし君はMicrosoftの070-461日本語版の認証試験に関する学習資料をしっかり勉強して、成功することも簡単になります。 それは NewValidDumpsの070-461日本語版問題集には実際の試験に出題される可能性がある問題をすべて含んでいて、しかもあなたをよりよく問題を理解させるように詳しい解析を与えますから。

MCTS 070-461 早速買いに行きましょう。

MCTS 070-461日本語版 - Querying Microsoft SQL Server 2012/2014 でも多くの人が合格するために大量の時間とエネルギーをかかって、無駄になります。 それは正確性が高くて、カバー率も広いです。あなたはNewValidDumpsの学習教材を購入した後、私たちは一年間で無料更新サービスを提供することができます。

それを利用したら、初めに試験を受けても、合格する自信を持つようになります。あなたは自分の職場の生涯にユニークな挑戦に直面していると思いましたら、Microsoftの070-461日本語版の認定試験に合格することが必要になります。NewValidDumpsはMicrosoftの070-461日本語版の認定試験を真実に、全面的に研究したサイトです。

Microsoft 070-461日本語版 - こうして、君は安心で試験の準備を行ってください。

NewValidDumpsについてどのくらい知っているのですか。NewValidDumpsの070-461日本語版試験問題集を利用したことがありますか。あるいは、知人からNewValidDumpsを聞いたことがありますか。IT認定試験に関連する参考書のプロな提供者として、NewValidDumpsは間違いなくあなたが今まで見た最高のサイトです。なぜこのように確かめるのですか。それはNewValidDumpsのように最良の070-461日本語版試験参考書を提供してあなたに試験に合格させるだけでなく、最高品質のサービスを提供してあなたに100％満足させることもできるサイトがないからです。

Microsoft 070-461日本語版「Querying Microsoft SQL Server 2012/2014」認証試験に合格することが簡単ではなくて、Microsoft 070-461日本語版証明書は君にとってはIT業界に入るの一つの手づるになるかもしれません。しかし必ずしも大量の時間とエネルギーで復習しなくて、弊社が丹精にできあがった問題集を使って、試験なんて問題ではありません。

070-461 PDF DEMO:

QUESTION NO: 1
You have an XML schema collection named Sales.InvoiceSchema.
You need to declare a variable of the XML type named invoice. The solution must ensure that the invoice is validated by using Sales.InvoiceSchema.
The solution must ensure that the invoice variable is validated by using Sales.InvoiceSchema schema.
Provide the correct code in the answer area.
Answer:
DECLARE @invoice XML(Sales.InvoiceSchema)

QUESTION NO: 2
You have a database that contains the tables shown in the exhibit. (Click the Exhibit button.)
You need to create a view named uv_CustomerFullName to meet the following requirements:
* The code must NOT include object delimiters.
* The view must be created in the Sales schema.
* Columns must only be referenced by using one-part names.
* The view must return the first name and the last name of all customers.
* The view must prevent the underlying structure of the customer table from being changed.
* The view must be able to resolve all referenced objects, regardless of the user's default schema.
Which code segment should you use?
To answer, type the correct code in the answer area.
A. CREATE VIEW Sales.uv_CustomerFullName
WITH SCHEMABINDING
AS
SELECT FirstName, LastName
B. CREATE VIEW Sales.uv_CustomerFullName
WITH SCHEMABINDING
AS
SELECT FirstName, LastName
FROM Sales.Customers
Answer: B
Reference:
http://msdn.microsoft.com/en-us/library/ms187956.aspx

QUESTION NO: 3
You are the administrator for a heavily-used OLTP Microsoft SQL Server database.
You are troubleshooting performance issues seen when using stored procedures in the database. The database stores millions of orders across thousands of customers. Some of the customers have large numbers of orders, while others have only one order. You update the statistics and perform defragmentation of all tables and indexes, but two stored procedures still have issues when accessing data.
p_GetCustomer accepts @companyID as a parameter. From the results of profiling, you know that 90 percent of the calls use the @companyid value of 5, while the other 10 percent of calls are evenly distributed across another 10000 values. While viewing the execution plan, you discover that a non- clustered index seek is used.
p_GetShipDate accepts @orderID as a parameter and returns the ship date for that order. You discover that the execution plan is performing a scan on a non-clustered index that has orderID as the index key.
You need to add appropriate query hints to each stored procedure to improve the performance.
What should you do? To answer, drag the appropriate procedures to the correct hints. Each procedure may be used once, more than once, or not at all. You may need to drag the split bar between panes or scroll to view content.
Answer:
Explanation:
Box 1: Optimize FOR..
OPTIMIZE FOR ( @variable_name { UNKNOWN | = literal_constant } [ , ...n ] ) Instructs the query optimizer to use a particular value for a local variable when the query is compiled and optimized. The value is used only during query optimization, and not during query execution.
Box 2: FORCESEEK
FORCESEEK [ (index_value(index_column_name [ ,... n ] )) ]
Specifies that the query optimizer use only an index seek operation as the access path to the data in the table or view.
References:
https://docs.microsoft.com/en-us/sql/t-sql/queries/hints-transact-sql-query?view=sql-server-2017
https://docs.microsoft.com/en-us/sql/t-sql/queries/hints-transact-sql-table?view=sql-server-2017

QUESTION NO: 4
You administer a Microsoft SQL Server 2012 database named ContosoDb. Tables are defined as shown in the exhibit. (Click the Exhibit button.)
You need to display rows from the Orders table for the Customers row having the CustomerId value set to 1 in the following XML format:
<row OrderId="1" OrderDate="2000-01-01T00:00:00" Amount="3400.00" Name="Customer A"
Country="Australia" />
<row OrderId="2" OrderDate="2001-01-01T00:00:00" Amount="4300.00" Name="Customer A"
Country="Australia" /> Which Transact-SQL query should you use?
A. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML RAW
B. SELECT Name AS 'Customers/Name', Country AS 'Customers/Country', OrderId, OrderDate,
Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId = 1 FOR XML PATH ('Customers')
C. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId - Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML AUTO, ELEMENTS
D. SELECT Name, Country, OrderId, OrderDate, Amount
FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML AUTO, ELEMENTS
E. SELECT Name, Country, OrderId, OrderDate, Amount
FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML AUTO
F. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML AUTO
G. SELECT Name AS '@Name', Country AS '@Country', OrderId, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML PATH ('Customers')
H. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML RAW, ELEMENTS
Answer: A

QUESTION NO: 5
Your database contains a table named Purchases. The table includes a DATETIME column named PurchaseTime that stores the date and time each purchase is made. There is a non-clustered index on the PurchaseTime column.
The business team wants a report that displays the total number of purchases made on the current day.
You need to write a query that will return the correct results in the most efficient manner.
Which Transact-SQL query should you use?
A. SELECT COUNT(*)
FROM Purchases
WHERE PurchaseTime = GETDATE()
B. SELECT COUNT(*)
FROM Purchases
WHERE PurchaseTime >= CONVERT(DATE, GETDATE())
AND PurchaseTime < DATEADD(DAY, 1, CONVERT(DATE, GETDATE()))
C. SELECT COUNT(*)
FROM Purchases
WHERE CONVERT(VARCHAR, PurchaseTime, 112) = CONVERT(VARCHAR, GETDATE(), 112)
D. SELECT COUNT(*)
FROM Purchases
WHERE PurchaseTime = CONVERT(DATE, GETDATE())
Answer: B
Explanation:
Two answers will return the correct results (the "WHERE CONVERT..." and "WHERE ... AND ... " answers).
The correct answer for Microsoft would be the answer that is most "efficient". Anybody have a clue as to which is most efficient? In the execution plan, the one that I've selected as the correct answer is the query with the shortest duration. Also, the query answer with "WHERE CONVERT..." threw warnings in the execution plan...something about affecting CardinalityEstimate and SeekPlan.
I also found this article, which leads me to believe that I have the correct answer:
http://technet.microsoft.com/en-us/library/ms181034.aspx

すなわちNewValidDumpsのSalesforce Customer-Data-Platform問題集を利用して試験の準備をすることです。 NetSuite NetSuite-Administrator - 今の社会の中で、ネット上で訓練は普及して、弊社は試験問題集を提供する多くのネットの一つでございます。 Salesforce ANC-201 - それはNewValidDumpsがすごく便利で、広い通用性があるからです。 SAP C_CPI_2404 - 試験問題と解答に関する質問があるなら、当社は直後に解決方法を差し上げます。 長年の努力を通じて、NewValidDumpsのMicrosoftのLinux Foundation HFCP認定試験の合格率が１００パーセントになっていました。

Updated: May 28, 2022