NewValidDumps Microsoftの70-461受験対策書試験問題集はあなたが自分の目標を達成することを助けられます。NewValidDumps Microsoftの70-461受験対策書問題資料は高度に認証されたIT領域の専門家の経験と創造を含めているものです。当社の製品は、すべての可能性のある問題を試させられます。 我々NewValidDumpsは一番効果的な方法を探してあなたにMicrosoftの70-461受験対策書試験に合格させます。弊社のMicrosoftの70-461受験対策書ソフトを購入するのを決めるとき、我々は各方面であなたに保障を提供します。 受験生は問題を選べ、テストの時間もコントロールできます。

MCSA 70-461 できるだけ100％の通過率を保証使用にしています。

短い時間に最も小さな努力で一番効果的にMicrosoftの70-461 - Querying Microsoft SQL Server 2012/2014受験対策書試験の準備をしたいのなら、NewValidDumpsのMicrosoftの70-461 - Querying Microsoft SQL Server 2012/2014受験対策書試験トレーニング資料を利用することができます。 ただ、社会に入るIT卒業生たちは自分能力の不足で、70-461 資格練習試験向けの仕事を探すのを悩んでいますか？それでは、弊社のMicrosoftの70-461 資格練習練習問題を選んで実用能力を速く高め、自分を充実させます。その結果、自信になる自己は面接のときに、面接官のいろいろな質問を気軽に回答できて、順調に70-461 資格練習向けの会社に入ります。

このトレーニング方法は受験生の皆さんに短い時間で予期の成果を取らせます。特に仕事しながら勉強している受験生たちにとって不可欠なツールです。NewValidDumpsトレーニング資料を選んだら、あなたは自分の夢を実現できます。

Microsoft 70-461受験対策書 - きっと君に失望させないと信じています。

今日、Microsoftの70-461受験対策書認定試験は、IT業界で多くの人に重視されています、それは、IT能力のある人の重要な基準の目安となっています。多くの人はMicrosoftの70-461受験対策書試験への準備に悩んでいます。この記事を読んだあなたはラッキーだと思います。あなたは最高の方法を探しましたから。私たちの強力なNewValidDumpsチームの開発するMicrosoftの70-461受験対策書ソフトを使用して試験に保障があります。まだ躊躇？最初に私たちのソフトウェアのデモを無料でダウンロードしよう。

我々は受験生の皆様により高いスピードを持っているかつ効率的なサービスを提供することにずっと力を尽くしていますから、あなたが貴重な時間を節約することに助けを差し上げます。NewValidDumps Microsoftの70-461受験対策書試験問題集はあなたに問題と解答に含まれている大量なテストガイドを提供しています。

70-461 PDF DEMO:

QUESTION NO: 1
You administer a Microsoft SQL Server database that supports a banking transaction management application.
You need to retrieve a list of account holders who live in cities that do not have a branch location.
Which Transact-SQL query or queries should you use? (Each correct answer presents a complete solution. Choose all that apply.)
A. SELECT AccountHolderID
FROM AccountHolder
WHERE CityID <> SOME (SELECT CityID FROM BranchMaster)
B. SELECT AccountHolderID
FROM AccountHolder
WHERE CityID <> ALL (SELECT CityID FROM BranchMaster)
C. SELECT AccountHolderID
FROM AccountHolder
WHERE CityID <> ANY (SELECT CityID FROM BranchMaster)
D. SELECT AccountHolderID
FROM AccountHolder
WHERE CityID NOT IN (SELECT CityID FROM BranchMaster)
Answer: B,D
Explanation:
Verified the answers as correct.

QUESTION NO: 2
Your database contains a table named Purchases. The table includes a DATETIME column named PurchaseTime that stores the date and time each purchase is made. There is a non-clustered index on the PurchaseTime column.
The business team wants a report that displays the total number of purchases made on the current day.
You need to write a query that will return the correct results in the most efficient manner.
Which Transact-SQL query should you use?
A. SELECT COUNT(*)
FROM Purchases
WHERE PurchaseTime = GETDATE()
B. SELECT COUNT(*)
FROM Purchases
WHERE PurchaseTime >= CONVERT(DATE, GETDATE())
AND PurchaseTime < DATEADD(DAY, 1, CONVERT(DATE, GETDATE()))
C. SELECT COUNT(*)
FROM Purchases
WHERE CONVERT(VARCHAR, PurchaseTime, 112) = CONVERT(VARCHAR, GETDATE(), 112)
D. SELECT COUNT(*)
FROM Purchases
WHERE PurchaseTime = CONVERT(DATE, GETDATE())
Answer: B
Explanation:
Two answers will return the correct results (the "WHERE CONVERT..." and "WHERE ... AND ... " answers).
The correct answer for Microsoft would be the answer that is most "efficient". Anybody have a clue as to which is most efficient? In the execution plan, the one that I've selected as the correct answer is the query with the shortest duration. Also, the query answer with "WHERE CONVERT..." threw warnings in the execution plan...something about affecting CardinalityEstimate and SeekPlan.
I also found this article, which leads me to believe that I have the correct answer:
http://technet.microsoft.com/en-us/library/ms181034.aspx

QUESTION NO: 3
You use Microsoft SQL Server 2012 database to develop a shopping cart application.
You need to invoke a table-valued function for each row returned by a query.
Which Transact-SQL operator should you use?
A. PIVOT
B. UNPIVOT
C. CROSS APPLY
D. CROSS JOIN
Answer: C
Reference:
http://msdn.microsoft.com/en-us/library/ms175156.aspx

QUESTION NO: 4
You administer a Microsoft SQL Server 2012 database named ContosoDb. Tables are defined as shown in the exhibit. (Click the Exhibit button.)
You need to display rows from the Orders table for the Customers row having the CustomerId value set to 1 in the following XML format:
<row OrderId="1" OrderDate="2000-01-01T00:00:00" Amount="3400.00" Name="Customer A"
Country="Australia" />
<row OrderId="2" OrderDate="2001-01-01T00:00:00" Amount="4300.00" Name="Customer A"
Country="Australia" /> Which Transact-SQL query should you use?
A. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML RAW
B. SELECT Name AS 'Customers/Name', Country AS 'Customers/Country', OrderId, OrderDate,
Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId = 1 FOR XML PATH ('Customers')
C. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId - Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML AUTO, ELEMENTS
D. SELECT Name, Country, OrderId, OrderDate, Amount
FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML AUTO, ELEMENTS
E. SELECT Name, Country, OrderId, OrderDate, Amount
FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML AUTO
F. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML AUTO
G. SELECT Name AS '@Name', Country AS '@Country', OrderId, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML PATH ('Customers')
H. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML RAW, ELEMENTS
Answer: A

QUESTION NO: 5
You need to create a query that meets the following requirements:
* The query must return a list of salespeople ranked by amount of sales and organized by postal code.
* The salesperson who has the highest amount of sales must be ranked first.
Part of the correct Transact-SQL has been provided in the answer area below. Enter the code in the answer area that resolves the problem and meets the stated goals or requirements. You can add code within code that has been provided as well as below it.
Use the 'Check Syntax' button to verify your work. Any syntax or spelling errors will be reported by line and character position.
A. 1 SELECT RowNumber() OVER(PARTITION BY PostalCode ORDER BY SalesYTd DESC) AS "Ranking",
2 p.LastName, s.SalesYTD, a.PostalCode
3 FROM Sales.SalesPerson AS a
etc
On line 1 add: RowNumber
One line 1 add: PARTITION BY
ROW_NUMBER() numbers the output of a result set. More specifically, returns the sequential number of a row within a partition of a result set, starting at 1 for the first row in each partition.
SYNTAX for OVER:
OVER (
[ <PARTITION BY clause> ]
[ <ORDER BY clause> ]
[ <ROW or RANGE clause> ]
)
Example: Using the OVER clause with the ROW_NUMBER function
The following example returns the ROW_NUMBER for sales representatives based on their assigned sales quota.
SELECT ROW_NUMBER() OVER(ORDER BY SUM(SalesAmountQuota) DESC) AS RowNumber,
FirstName, LastName, CONVERT(varchar(13), SUM(SalesAmountQuota),1) AS SalesQuota FROM dbo.DimEmployee AS e INNER JOIN dbo.FactSalesQuota AS sq ON e.EmployeeKey = sq.EmployeeKey
WHERE e.SalesPersonFlag = 1 GROUP BY LastName, FirstName; Here is a partial result set.
RowNumber FirstName LastName SalesQuota
--------- --------- ------------------ -------------
1 Jillian Carson 12,198,000.00
2 Linda Mitchell 11,786,000.00
3 Michael Blythe 11,162,000.00
4 Jae Pak 10,514,000.00
B. 1 SELECT RowNumber() OVER(PARTITION BY PostalCode ORDER BY SalesYTd DESC) AS "Ranking",
2 p.LastName, s.SalesYTD, a.PostalCode
3 FROM Sales.SalesPerson AS a
etc
More specifically, returns the sequential number of a row within a partition of a result set, starting at
1 for the first row in each partition.
SYNTAX for OVER:
OVER (
[ <PARTITION BY clause> ]
[ <ORDER BY clause> ]
[ <ROW or RANGE clause> ]
)
Example: Using the OVER clause with the ROW_NUMBER function
The following example returns the ROW_NUMBER for sales representatives based on their assigned sales quota.
SELECT ROW_NUMBER() OVER(ORDER BY SUM(SalesAmountQuota) DESC) AS RowNumber,
FirstName, LastName, CONVERT(varchar(13), SUM(SalesAmountQuota),1) AS SalesQuota FROM dbo.DimEmployee AS e INNER JOIN dbo.FactSalesQuota AS sq ON e.EmployeeKey = sq.EmployeeKey
WHERE e.SalesPersonFlag = 1 GROUP BY LastName, FirstName; Here is a partial result set.
RowNumber FirstName LastName SalesQuota
--------- --------- ------------------ -------------
1 Jillian Carson 12,198,000.00
2 Linda Mitchell 11,786,000.00
3 Michael Blythe 11,162,000.00
4 Jae Pak 10,514,000.00
Answer: A
Explanation:
References:
https://docs.microsoft.com/en-us/sql/t-sql/functions/row-number-transact-sql
https://docs.microsoft.com/en-us/sql/t-sql/queries/select-over-clause-transact-sql

PRINCE2 PRINCE2-Foundation-JPN - あなたはデモで我々のソフトの効果を体験することができます。 Salesforce Salesforce-Sales-Representative-JPN - ためらわずに速くあなたのショッピングカートに入れてください。 Cisco 300-425 - 現在あなたもこのような珍しい資料を得られます。 NewValidDumpsのMicrosoftのHP HP2-I73試験トレーニング資料はインターネットでの全てのトレーニング資料のリーダーです。 これなので、今から我々社NewValidDumpsのSalesforce Platform-App-Builder試験に合格するのに努力していきます。

Updated: May 28, 2022