NewValidDumpsにはIT専門家が組み立てられた団体があります。彼らは受験生の皆さんの重要な利益が保障できるように専門的な知識と豊富な経験を活かして特別に適用性が強いトレーニング資料を研究します。その資料が即ちMicrosoftの70-461テキスト試験トレーニング資料で、問題集と解答に含まれていますから。 Microsoftの認証資格は最近ますます人気になっていますね。国際的に認可された資格として、Microsoftの認定試験を受ける人も多くなっています。 NewValidDumpsのMicrosoftの70-461テキスト試験トレーニング資料を購入しましたから。

MCSA 70-461 IT認定試験には多くの種類があります。

我々はあなたに提供するのは最新で一番全面的なMicrosoftの70-461 - Querying Microsoft SQL Server 2012/2014テキスト問題集で、最も安全な購入保障で、最もタイムリーなMicrosoftの70-461 - Querying Microsoft SQL Server 2012/2014テキスト試験のソフトウェアの更新です。 学歴はただ踏み台だけで、あなたの地位を確保できる礎は実力です。IT職員としているあなたがどうやって自分自身の実力を養うのですか。

我々の承諾だけでなく、お客様に最も全面的で最高のサービスを提供します。Microsoftの70-461テキストの購入の前にあなたの無料の試しから、購入の後での一年間の無料更新まで我々はあなたのMicrosoftの70-461テキスト試験に一番信頼できるヘルプを提供します。Microsoftの70-461テキスト試験に失敗しても、我々はあなたの経済損失を減少するために全額で返金します。

Microsoft 70-461テキスト - ここには、私たちは君の需要に応じます。

社会と経済の発展につれて、多くの人はIT技術を勉強します。なぜならば、IT職員にとって、Microsoftの70-461テキスト資格証明書があるのは肝心な指標であると言えます。自分の能力を証明するために、70-461テキスト試験に合格するのは不可欠なことです。弊社の70-461テキスト真題を入手して、試験に合格する可能性が大きくなります。

NewValidDumpsは君のもっと輝い将来に助けられます。簡単にMicrosoftの70-461テキスト認定試験に合格したいか。

70-461 PDF DEMO:

QUESTION NO: 1
You use Microsoft SQL Server 2012 database to develop a shopping cart application.
You need to invoke a table-valued function for each row returned by a query.
Which Transact-SQL operator should you use?
A. PIVOT
B. UNPIVOT
C. CROSS APPLY
D. CROSS JOIN
Answer: C
Reference:
http://msdn.microsoft.com/en-us/library/ms175156.aspx

QUESTION NO: 2
You administer a Microsoft SQL Server database that supports a banking transaction management application.
You need to retrieve a list of account holders who live in cities that do not have a branch location.
Which Transact-SQL query or queries should you use? (Each correct answer presents a complete solution. Choose all that apply.)
A. SELECT AccountHolderID
FROM AccountHolder
WHERE CityID <> SOME (SELECT CityID FROM BranchMaster)
B. SELECT AccountHolderID
FROM AccountHolder
WHERE CityID <> ALL (SELECT CityID FROM BranchMaster)
C. SELECT AccountHolderID
FROM AccountHolder
WHERE CityID <> ANY (SELECT CityID FROM BranchMaster)
D. SELECT AccountHolderID
FROM AccountHolder
WHERE CityID NOT IN (SELECT CityID FROM BranchMaster)
Answer: B,D
Explanation:
Verified the answers as correct.

QUESTION NO: 3
You need to create a query that meets the following requirements:
* The query must return a list of salespeople ranked by amount of sales and organized by postal code.
* The salesperson who has the highest amount of sales must be ranked first.
Part of the correct Transact-SQL has been provided in the answer area below. Enter the code in the answer area that resolves the problem and meets the stated goals or requirements. You can add code within code that has been provided as well as below it.
Use the 'Check Syntax' button to verify your work. Any syntax or spelling errors will be reported by line and character position.
A. 1 SELECT RowNumber() OVER(PARTITION BY PostalCode ORDER BY SalesYTd DESC) AS "Ranking",
2 p.LastName, s.SalesYTD, a.PostalCode
3 FROM Sales.SalesPerson AS a
etc
On line 1 add: RowNumber
One line 1 add: PARTITION BY
ROW_NUMBER() numbers the output of a result set. More specifically, returns the sequential number of a row within a partition of a result set, starting at 1 for the first row in each partition.
SYNTAX for OVER:
OVER (
[ <PARTITION BY clause> ]
[ <ORDER BY clause> ]
[ <ROW or RANGE clause> ]
)
Example: Using the OVER clause with the ROW_NUMBER function
The following example returns the ROW_NUMBER for sales representatives based on their assigned sales quota.
SELECT ROW_NUMBER() OVER(ORDER BY SUM(SalesAmountQuota) DESC) AS RowNumber,
FirstName, LastName, CONVERT(varchar(13), SUM(SalesAmountQuota),1) AS SalesQuota FROM dbo.DimEmployee AS e INNER JOIN dbo.FactSalesQuota AS sq ON e.EmployeeKey = sq.EmployeeKey
WHERE e.SalesPersonFlag = 1 GROUP BY LastName, FirstName; Here is a partial result set.
RowNumber FirstName LastName SalesQuota
--------- --------- ------------------ -------------
1 Jillian Carson 12,198,000.00
2 Linda Mitchell 11,786,000.00
3 Michael Blythe 11,162,000.00
4 Jae Pak 10,514,000.00
B. 1 SELECT RowNumber() OVER(PARTITION BY PostalCode ORDER BY SalesYTd DESC) AS "Ranking",
2 p.LastName, s.SalesYTD, a.PostalCode
3 FROM Sales.SalesPerson AS a
etc
More specifically, returns the sequential number of a row within a partition of a result set, starting at
1 for the first row in each partition.
SYNTAX for OVER:
OVER (
[ <PARTITION BY clause> ]
[ <ORDER BY clause> ]
[ <ROW or RANGE clause> ]
)
Example: Using the OVER clause with the ROW_NUMBER function
The following example returns the ROW_NUMBER for sales representatives based on their assigned sales quota.
SELECT ROW_NUMBER() OVER(ORDER BY SUM(SalesAmountQuota) DESC) AS RowNumber,
FirstName, LastName, CONVERT(varchar(13), SUM(SalesAmountQuota),1) AS SalesQuota FROM dbo.DimEmployee AS e INNER JOIN dbo.FactSalesQuota AS sq ON e.EmployeeKey = sq.EmployeeKey
WHERE e.SalesPersonFlag = 1 GROUP BY LastName, FirstName; Here is a partial result set.
RowNumber FirstName LastName SalesQuota
--------- --------- ------------------ -------------
1 Jillian Carson 12,198,000.00
2 Linda Mitchell 11,786,000.00
3 Michael Blythe 11,162,000.00
4 Jae Pak 10,514,000.00
Answer: A
Explanation:
References:
https://docs.microsoft.com/en-us/sql/t-sql/functions/row-number-transact-sql
https://docs.microsoft.com/en-us/sql/t-sql/queries/select-over-clause-transact-sql

QUESTION NO: 4
Your database contains a table named Purchases. The table includes a DATETIME column named PurchaseTime that stores the date and time each purchase is made. There is a non-clustered index on the PurchaseTime column.
The business team wants a report that displays the total number of purchases made on the current day.
You need to write a query that will return the correct results in the most efficient manner.
Which Transact-SQL query should you use?
A. SELECT COUNT(*)
FROM Purchases
WHERE PurchaseTime = GETDATE()
B. SELECT COUNT(*)
FROM Purchases
WHERE PurchaseTime >= CONVERT(DATE, GETDATE())
AND PurchaseTime < DATEADD(DAY, 1, CONVERT(DATE, GETDATE()))
C. SELECT COUNT(*)
FROM Purchases
WHERE CONVERT(VARCHAR, PurchaseTime, 112) = CONVERT(VARCHAR, GETDATE(), 112)
D. SELECT COUNT(*)
FROM Purchases
WHERE PurchaseTime = CONVERT(DATE, GETDATE())
Answer: B
Explanation:
Two answers will return the correct results (the "WHERE CONVERT..." and "WHERE ... AND ... " answers).
The correct answer for Microsoft would be the answer that is most "efficient". Anybody have a clue as to which is most efficient? In the execution plan, the one that I've selected as the correct answer is the query with the shortest duration. Also, the query answer with "WHERE CONVERT..." threw warnings in the execution plan...something about affecting CardinalityEstimate and SeekPlan.
I also found this article, which leads me to believe that I have the correct answer:
http://technet.microsoft.com/en-us/library/ms181034.aspx

QUESTION NO: 5
You administer a Microsoft SQL Server instance that will support several databases.
You need to ensure that every new database created has a data type named postalcode that contains the same attributes.
What should you do?
A. Create a user-defined data type on the master database.
B. Create a user-defined type on the model database.
C. Create a user-defined type on the master database.
D. Create a user-defined data type on the model database.
Answer: D
Explanation:
One option is to create SQL Server user defined data types.
One trick with new databases is to create the objects in the model database, so as new databases are created the user defined data types will automatically be available.
References: https://www.mssqltips.com/sqlservertip/1628/sql-server-user-defined-data-types-rules- and-defaults/

Microsoft SC-100J - 我々NewValidDumpsは一番行き届いたアフタサービスを提供します。 NewValidDumpsの MicrosoftのMicrosoft MS-102試験トレーニング資料は高度に認証されたIT領域の専門家の経験と創造を含めているものです。 我々社サイトのMicrosoft　Salesforce CRT-403問題庫は最新かつ最完備な勉強資料を有して、あなたに高品質のサービスを提供するのはSalesforce CRT-403資格認定試験の成功にとって唯一の選択です。 我々のソフトを利用してMicrosoftのCompTIA 220-1101試験失敗したら全額で返金するという承諾は不自信ではなく、我々のお客様への誠な態度を表わしたいです。 あなたは無料でCisco 700-250復習教材をダウンロードしたいですか？もちろん、回答ははいです。

Updated: May 28, 2022