70-461認証Pdf資料 資格取得

Microsoft 70-461認証Pdf資料資格認定はIT技術領域に従事する人に必要があります。我々社のMicrosoft 70-461認証Pdf資料試験練習問題はあなたに試験うま合格できるのを支援します。あなたの取得したMicrosoft 70-461認証Pdf資料資格認定は、仕事中に核心技術知識を同僚に認可されるし、あなたの技術信頼度を増強できます。 NewValidDumpsのMicrosoftの70-461認証Pdf資料試験トレーニング資料を持っていたら、試験に対する充分の準備がありますから、安心に利用したください。NewValidDumpsは優れたIT情報のソースを提供するサイトです。 70-461認証Pdf資料認定試験の問題集は大勢の人の注目を集め、とても人気がある商品です。

MCSA 70-461 君の初めての合格を目標にします。

NewValidDumpsのMicrosoftの70-461 - Querying Microsoft SQL Server 2012/2014認証Pdf資料試験トレーニング資料は試験問題と解答を含まれて、豊富な経験を持っているIT業種の専門家が長年の研究を通じて作成したものです。 多くの人々は高い難度のIT認証試験に合格するのは専門の知識が必要だと思います。それは確かにそうですが、その知識を身につけることは難しくないとといわれています。

我々の誠意を信じてください。あなたが順調に試験に合格するように。時間とお金の集まりより正しい方法がもっと大切です。

Microsoft 70-461認証Pdf資料 - そうだったら、NewValidDumpsを利用したください。

NewValidDumps を選択して100%の合格率を確保することができて、もし試験に失敗したら、NewValidDumpsが全額で返金いたします。

NewValidDumpsのMicrosoftの70-461認証Pdf資料試験トレーニング資料はあなたの成功への第一歩です。この資料を持っていたら、難しいMicrosoftの70-461認証Pdf資料認定試験に合格することができるようになります。

70-461 PDF DEMO:

QUESTION NO: 1
You administer a Microsoft SQL Server database that supports a banking transaction management application.
You need to retrieve a list of account holders who live in cities that do not have a branch location.
Which Transact-SQL query or queries should you use? (Each correct answer presents a complete solution. Choose all that apply.)
A. SELECT AccountHolderID
FROM AccountHolder
WHERE CityID <> SOME (SELECT CityID FROM BranchMaster)
B. SELECT AccountHolderID
FROM AccountHolder
WHERE CityID <> ALL (SELECT CityID FROM BranchMaster)
C. SELECT AccountHolderID
FROM AccountHolder
WHERE CityID <> ANY (SELECT CityID FROM BranchMaster)
D. SELECT AccountHolderID
FROM AccountHolder
WHERE CityID NOT IN (SELECT CityID FROM BranchMaster)
Answer: B,D
Explanation:
Verified the answers as correct.

QUESTION NO: 2
Your database contains a table named Purchases. The table includes a DATETIME column named PurchaseTime that stores the date and time each purchase is made. There is a non-clustered index on the PurchaseTime column.
The business team wants a report that displays the total number of purchases made on the current day.
You need to write a query that will return the correct results in the most efficient manner.
Which Transact-SQL query should you use?
A. SELECT COUNT(*)
FROM Purchases
WHERE PurchaseTime = GETDATE()
B. SELECT COUNT(*)
FROM Purchases
WHERE PurchaseTime >= CONVERT(DATE, GETDATE())
AND PurchaseTime < DATEADD(DAY, 1, CONVERT(DATE, GETDATE()))
C. SELECT COUNT(*)
FROM Purchases
WHERE CONVERT(VARCHAR, PurchaseTime, 112) = CONVERT(VARCHAR, GETDATE(), 112)
D. SELECT COUNT(*)
FROM Purchases
WHERE PurchaseTime = CONVERT(DATE, GETDATE())
Answer: B
Explanation:
Two answers will return the correct results (the "WHERE CONVERT..." and "WHERE ... AND ... " answers).
The correct answer for Microsoft would be the answer that is most "efficient". Anybody have a clue as to which is most efficient? In the execution plan, the one that I've selected as the correct answer is the query with the shortest duration. Also, the query answer with "WHERE CONVERT..." threw warnings in the execution plan...something about affecting CardinalityEstimate and SeekPlan.
I also found this article, which leads me to believe that I have the correct answer:
http://technet.microsoft.com/en-us/library/ms181034.aspx

QUESTION NO: 3
You use Microsoft SQL Server 2012 database to develop a shopping cart application.
You need to invoke a table-valued function for each row returned by a query.
Which Transact-SQL operator should you use?
A. PIVOT
B. UNPIVOT
C. CROSS APPLY
D. CROSS JOIN
Answer: C
Reference:
http://msdn.microsoft.com/en-us/library/ms175156.aspx

QUESTION NO: 4
You administer a Microsoft SQL Server 2012 database named ContosoDb. Tables are defined as shown in the exhibit. (Click the Exhibit button.)
You need to display rows from the Orders table for the Customers row having the CustomerId value set to 1 in the following XML format:
<row OrderId="1" OrderDate="2000-01-01T00:00:00" Amount="3400.00" Name="Customer A"
Country="Australia" />
<row OrderId="2" OrderDate="2001-01-01T00:00:00" Amount="4300.00" Name="Customer A"
Country="Australia" /> Which Transact-SQL query should you use?
A. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML RAW
B. SELECT Name AS 'Customers/Name', Country AS 'Customers/Country', OrderId, OrderDate,
Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId = 1 FOR XML PATH ('Customers')
C. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId - Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML AUTO, ELEMENTS
D. SELECT Name, Country, OrderId, OrderDate, Amount
FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML AUTO, ELEMENTS
E. SELECT Name, Country, OrderId, OrderDate, Amount
FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML AUTO
F. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML AUTO
G. SELECT Name AS '@Name', Country AS '@Country', OrderId, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML PATH ('Customers')
H. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML RAW, ELEMENTS
Answer: A

QUESTION NO: 5
You need to create a query that meets the following requirements:
* The query must return a list of salespeople ranked by amount of sales and organized by postal code.
* The salesperson who has the highest amount of sales must be ranked first.
Part of the correct Transact-SQL has been provided in the answer area below. Enter the code in the answer area that resolves the problem and meets the stated goals or requirements. You can add code within code that has been provided as well as below it.
Use the 'Check Syntax' button to verify your work. Any syntax or spelling errors will be reported by line and character position.
A. 1 SELECT RowNumber() OVER(PARTITION BY PostalCode ORDER BY SalesYTd DESC) AS "Ranking",
2 p.LastName, s.SalesYTD, a.PostalCode
3 FROM Sales.SalesPerson AS a
etc
On line 1 add: RowNumber
One line 1 add: PARTITION BY
ROW_NUMBER() numbers the output of a result set. More specifically, returns the sequential number of a row within a partition of a result set, starting at 1 for the first row in each partition.
SYNTAX for OVER:
OVER (
[ <PARTITION BY clause> ]
[ <ORDER BY clause> ]
[ <ROW or RANGE clause> ]
)
Example: Using the OVER clause with the ROW_NUMBER function
The following example returns the ROW_NUMBER for sales representatives based on their assigned sales quota.
SELECT ROW_NUMBER() OVER(ORDER BY SUM(SalesAmountQuota) DESC) AS RowNumber,
FirstName, LastName, CONVERT(varchar(13), SUM(SalesAmountQuota),1) AS SalesQuota FROM dbo.DimEmployee AS e INNER JOIN dbo.FactSalesQuota AS sq ON e.EmployeeKey = sq.EmployeeKey
WHERE e.SalesPersonFlag = 1 GROUP BY LastName, FirstName; Here is a partial result set.
RowNumber FirstName LastName SalesQuota
--------- --------- ------------------ -------------
1 Jillian Carson 12,198,000.00
2 Linda Mitchell 11,786,000.00
3 Michael Blythe 11,162,000.00
4 Jae Pak 10,514,000.00
B. 1 SELECT RowNumber() OVER(PARTITION BY PostalCode ORDER BY SalesYTd DESC) AS "Ranking",
2 p.LastName, s.SalesYTD, a.PostalCode
3 FROM Sales.SalesPerson AS a
etc
More specifically, returns the sequential number of a row within a partition of a result set, starting at
1 for the first row in each partition.
SYNTAX for OVER:
OVER (
[ <PARTITION BY clause> ]
[ <ORDER BY clause> ]
[ <ROW or RANGE clause> ]
)
Example: Using the OVER clause with the ROW_NUMBER function
The following example returns the ROW_NUMBER for sales representatives based on their assigned sales quota.
SELECT ROW_NUMBER() OVER(ORDER BY SUM(SalesAmountQuota) DESC) AS RowNumber,
FirstName, LastName, CONVERT(varchar(13), SUM(SalesAmountQuota),1) AS SalesQuota FROM dbo.DimEmployee AS e INNER JOIN dbo.FactSalesQuota AS sq ON e.EmployeeKey = sq.EmployeeKey
WHERE e.SalesPersonFlag = 1 GROUP BY LastName, FirstName; Here is a partial result set.
RowNumber FirstName LastName SalesQuota
--------- --------- ------------------ -------------
1 Jillian Carson 12,198,000.00
2 Linda Mitchell 11,786,000.00
3 Michael Blythe 11,162,000.00
4 Jae Pak 10,514,000.00
Answer: A
Explanation:
References:
https://docs.microsoft.com/en-us/sql/t-sql/functions/row-number-transact-sql
https://docs.microsoft.com/en-us/sql/t-sql/queries/select-over-clause-transact-sql

Network Appliance NS0-163 - 早くNewValidDumpsの問題集を君の手に入れましょう。 HP HPE2-B07 - NewValidDumpsの問題集には、実際の試験に出る可能性がある問題が全部含まれていますから、問題集における問題を覚える限り、簡単に試験に合格することができます。 VMware 3V0-31.22 - 君が後悔しないようにもっと少ないお金を使って大きな良い成果を取得するためにNewValidDumpsを選択してください。 いまCloud Security Alliance CCZT試験に合格するショートカットを教えてあげますから。 NewValidDumps のMicrosoftのDatabricks Databricks-Certified-Professional-Data-Engineer問題集はシラバスに従って、それにDatabricks Databricks-Certified-Professional-Data-Engineer認定試験の実際に従って、あなたがもっとも短い時間で最高かつ最新の情報をもらえるように、弊社はトレーニング資料を常にアップグレードしています。

Updated: May 28, 2022

70-461認証Pdf資料 & Microsoft Querying Microsoft SQL Server 2012/2014日本語解説集

PDF問題と解答

試験コード:70-461
試験名称:Querying Microsoft SQL Server 2012/2014
最近更新時間:2024-03-28
問題と解答:全 252
Microsoft 70-461 更新版

  ダウンロード


 

模擬試験

試験コード:70-461
試験名称:Querying Microsoft SQL Server 2012/2014
最近更新時間:2024-03-28
問題と解答:全 252
Microsoft 70-461 テスト難易度

  ダウンロード


 

オンライン版

試験コード:70-461
試験名称:Querying Microsoft SQL Server 2012/2014
最近更新時間:2024-03-28
問題と解答:全 252
Microsoft 70-461 試験対策

  ダウンロード


 

70-461 テスト模擬問題集

70-461 受験料 関連認定