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SCMA 310-814 早くNewValidDumpsの問題集を君の手に入れましょう。

仕事に忙しいから試験の準備をする時間はあまりないとしたら、絶対NewValidDumpsの310-814 - MySQL 5.0, 5.1 and 5.5 Certified Associate Exam練習問題問題集を見逃すことはできないです。 君が後悔しないようにもっと少ないお金を使って大きな良い成果を取得するためにNewValidDumpsを選択してください。NewValidDumpsはまた一年間に無料なサービスを更新いたします。

気楽に試験に合格したければ、はやく試しに来てください。310-814練習問題認定試験に合格することは難しいようですね。試験を申し込みたいあなたは、いまどうやって試験に準備すべきなのかで悩んでいますか。

SUNのSUN 310-814練習問題試験に合格するのは最良の方法の一です。

NewValidDumpsの310-814練習問題問題集は多くの受験生に検証されたものですから、高い成功率を保証できます。もしこの問題集を利用してからやはり試験に不合格になってしまえば、NewValidDumpsは全額で返金することができます。あるいは、無料で試験310-814練習問題問題集を更新してあげるのを選択することもできます。こんな保障がありますから、心配する必要は全然ないですよ。

SUNの310-814練習問題試験の資料のいくつかのバーションのデモは我々のウェブサイトで無料でダウンロードできます。あなたの愛用する版をやってみよう。

310-814 PDF DEMO:

QUESTION NO: 1
FreeE
Consider the exhibit given below:
Which of the following queries will return the name of the customer who placed the highest amount of orders and the total order amount?
A. SELECT CUSTOMER,MAX(UNITPRICE*QUANTITY) AS "TOTAL"
FROM ORDERS
GROUP BY CUSTOMER
/
B. SELECT CUSTOMER,SUM(UNITPRICE*QUANTITY) AS "TOTAL"
FROM ORDERS
WHERE SUM(UNITPRICE*QUANTITY)=
(SELECT MAX(SUM(UNITPRICE*QUANTITY))
FROM ORDERS
GROUP BY CUSTOMER)
GROUP BY CUSTOMER
/
C. SELECT CUSTOMER,SUM(UNITPRICE*QUANTITY) AS "TOTAL"
FROM ORDERS
GROUP BY CUSTOMER
HAVING SUM(UNITPRICE*QUANTITY)=
(SELECT MAX(SUM(UNITPRICE*QUANTITY))
FROM ORDERS
GROUP BY CUSTOMER)
/
D. SELECT CUSTOMER,SUM(UNITPRICE*QUANTITY) AS "TOTAL"
FROM ORDERS
GROUP BY CUSTOMER
HAVING SUM(UNITPRICE*QUANTITY)=
(SELECT SUM(UNITPRICE*QUANTITY)
FROM ORDERS
GROUP BY CUSTOMER)
/
Answer: C

QUESTION NO: 2
You work as a Database Administrator for a company. The company uses MySQL as its database.
You have created a table named Employees in the database. You want to create a list of employees working in the organization, but you do not want to display any duplicate row in the report. Which of the following statements will help you to accomplish the task?
A. SELECTemp_id, emp_name FROM Employees ORDER BY emp_id;
B. SELECTemp_id, emp_name FROM Employees;
C. SELECT DISTINCTemp_id, emp_name FROM Employees;
D. SELECTemp_id, emp_name FROM Employees GROUP BY emp_id;
Answer: C

QUESTION NO: 3
Which of the following will be true about a table column if you plan to create an index on that column?
Each correct answer represents a complete solution. Choose all that apply.
A. The column is often used in the WHERE clause of SQL statements.
B. The column contains very small number of NULL values.
C. The table is updated frequently.
D. The column should contain a wide range of values.
Answer: A,D

QUESTION NO: 4
Adam works as a Database Administrator for a company. The company uses MySQL as its database. Adam has created a table named Employees in the database. He wants to retrieve the information of those employees who have at least one person reporting to them. Which of the following queries will Adam execute to accomplish the task?
A. SELECTemployee_id, last_name, job_id, department_id FROM Employees WHERE employee_id
EXISTS (SELECT manager_id WHERE manager_id is NULL);
B. SELECTemployee_id, last_name, job_id, department_id FROM Employees HAVING employee_id
IN (SELECT manager_id FROM Employees WHERE manager_id is NOT NULL);
C. SELECTemployee_id, last_name, job_id, department_id FROM Employees outer WHERE
EXISTS
(SELECT 'x' FROM Employees WHERE manager_id = outer.employee_id);
D. SELECTemployee_id, last_name, job_id, department_id FROM Employees WHERE employee_idIN
(SELECT manager_id WHERE manager_id is NOT NULL);
Answer: C

QUESTION NO: 5
You work as a Database Administrator for a company. The company uses MySQL as its database.
You have written two statements, which are as follows:
1. SELECT DISTINCT OBJECT_TYPE
FROM USER_OBJECTS;
2. SELECT OBJECT_TYPE
FROM ALL_OBJECTS;
Which of the following options explains the difference between the results of these two statements? Each correct answer represents a complete solution. Choose all that apply.
A. The first statement will display distinct object types that can be accessed by the user.
B. The second statement will display all object types that a user can access.
C. The first statement will display distinct object types owned by a user.
D. The second statement will display all object types owned by a user.
Answer: B,C

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Updated: May 27, 2022