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1Z0-141 PDF DEMO:

QUESTION NO: 1
View the Exhibit. You are coding a When-New-Form-Instance trigger to populate a hierarchical tree item called Emp_Tree that should initially appear as shown in the exhibit. Mr. King, the president of the company, is the only employee who does not have a manager. In the trigger, you declare a variable called rg_emps that is of the RECORDGROUP data type. You will use this record group to populate the tree. You use the following code to create the record group: rg_emps :=
Create_Group_From_Query('rg_emps', 'select 1, level, last_name, NULL, to_char(employee_id) from employees connect by prior employee_id = manager_id start with manager_id is null'); You then programmatically populate the record group, and then populate the tree with the record group. You run the form to test it. Will the tree initially appear as shown? If not, why not?
A.Yes, the tree will appear as shown.
B.No. The first element selected in the select statement should be 4 because you want four levels of the tree to be displayed.
C.No. You should eliminate the last element selected in the select statement, because you do not want to display the employee ID.
D.No. The "connect by" statement should be "connect by prior manager_id = employee_id".
Correct:A

QUESTION NO: 2
To centralize some of your processing, you decide to write PL/SQL library modules that contain procedures that can be called from form triggers or menu items. You need to populate some fields based on values in other fields. Which code do you use?
A.IF FIND_ITEM('ORDERS.order_total') > 10000 THEN FIND_ITEM('ORDERS.large_order') := 'Y';
MESSAGE('WARNING - large order!'); END IF;
B.IF :ORDERS.order_total > 10000 THEN :ORDERS.large_order := 'Y'; MESSAGE('WARNING - large order!'); END IF;
C.IF 'ORDERS.order_total' > 10000 THEN 'ORDERS.large_order' := 'Y'; MESSAGE('WARNING - large order!'); END IF;
D.IF :ORDERS.order_total > 10000 THEN COPY('ORDERS.large_order','Y'); MESSAGE('WARNING - large order!'); END IF;
E.IF NAME_IN('ORDERS.order_total') > 10000 THEN COPY('Y','ORDERS.large_order');
MESSAGE('WARNING - large order!'); END IF;
Correct:E

QUESTION NO: 3
View the Exhibit. The EMPLOYEES table contains 100 records. You are developing a Human
Resources form that has an Employees block with properties as shown in the exhibit. When you run the form and execute a query in the Employees block, approximately how many network round trips will be made to the server before records are displayed in the block?
A.1
B.2
C.10
D.50
E.100
Correct:C

QUESTION NO: 4
In the Orders form you define five LOVs, and you create one button to be used to display any of the LOVs. The button is enabled only when the user navigates to a field with an attached LOV. If the user supplies only part of the required input data, the LOVs use that input as search criteria to automatically reduce the LOV contents. If the LOVs hold only one value that can possibly match user-supplied input, then the LOVs auto-complete the input field and are not displayed. Which built-in and properties should you use to display the LOVs?
A.Use the List_Values(RESTRICT) built-in, and set the Mouse Navigate property value to NO.
B.Use the List_Values(RESTRICT) built-in, and set the Mouse Navigate property value to YES.
C.Use the List_Values(NO_RESTRICT) built-in, and set the Mouse Navigate property value to NO.
D.Use the List_Values(NO_RESTRICT) built-in, and set the Mouse Navigate property value to YES.
E.Use the Show_LOV built-in, and set the Mouse Navigate property value to YES.
F.Use the Show_LOV built-in, and set the Mouse Navigate property value to NO.
Correct:A

QUESTION NO: 5
View the Exhibit. You are modifying the New_Orders form. You want to change the navigation order of the Orders block so that Order_Status is between Order_Date and Order_Mode in the navigation order. You attempt to drag the Order_Status item in the Object Navigator (as shown in the exhibit), but Forms does not allow you to release the item in the desired position. Why is this happening, and what can you do to change the navigation order?
A.Because the data block is subclassed, you cannot change the order of items in the object navigator, but you can change item properties to affect the navigation order.
B.Because the data block is subclassed, you can only drag objects to a lower position in the Object
Navigator, so you can drag Order_Mode and Customer_Id to a position below Order_Status.
C.Because the data block is subclassed, you will have to delete the object and then create it again in the desired position.
D.Because the item is subclassed, you cannot change any of its properties.
Correct:A

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Updated: May 26, 2022

1Z0-141日本語参考、Oracle 1Z0-141真実試験 & Oracle9I Forma Developer:Build Internet Applications

PDF問題と解答

試験コード:1Z0-141
試験名称:Oracle9i forma Developer:build internet applications
最近更新時間:2024-06-01
問題と解答:全 138
Oracle 1Z0-141 模擬試験

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模擬試験

試験コード:1Z0-141
試験名称:Oracle9i forma Developer:build internet applications
最近更新時間:2024-06-01
問題と解答:全 138
Oracle 1Z0-141 関連問題資料

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オンライン版

試験コード:1Z0-141
試験名称:Oracle9i forma Developer:build internet applications
最近更新時間:2024-06-01
問題と解答:全 138
Oracle 1Z0-141 受験記

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1Z0-141 日本語試験情報