NewValidDumpsの問題集を買ったら1年間の無料オンラインのアップデートを提供する一方で、試験に失敗したら、お客様に全額で返金いたします。 あなたに成功に近づいて、夢の楽園に一歩一歩進めさせられます。NewValidDumps Microsoftの070-461認定資格試験トレーニング資料というのは一体なんでしょうか。 あなたが決して後悔しないことを保証します。

MCTS 070-461 明るい未来を準備してあげます。

したがって、NewValidDumpsの070-461 - Querying Microsoft SQL Server 2012/2014認定資格問題集も絶えずに更新されています。 NewValidDumpsというサイトは素晴らしいソースサイトで、Microsoftの070-461 関連日本語内容の試験材料、研究材料、技術材料や詳しい解答に含まれています。問題集が提供したサイトは近年で急速に増加しています。

NewValidDumpsの070-461認定資格問題集は多くの受験生に検証されたものですから、高い成功率を保証できます。もしこの問題集を利用してからやはり試験に不合格になってしまえば、NewValidDumpsは全額で返金することができます。あるいは、無料で試験070-461認定資格問題集を更新してあげるのを選択することもできます。

Microsoft 070-461認定資格 - そうしたら速くNewValidDumpsを選びましょう。

なぜ受験生のほとんどはNewValidDumpsを選んだのですか。それはNewValidDumpsがすごく便利で、広い通用性があるからです。NewValidDumpsのITエリートたちは彼らの専門的な目で、最新的なMicrosoftの070-461認定資格試験トレーニング資料に注目していて、うちのMicrosoftの070-461認定資格問題集の高い正確性を保証するのです。もし君はいささかな心配することがあるなら、あなたはうちの商品を購入する前に、NewValidDumpsは無料でサンプルを提供することができます。

NewValidDumpsのMicrosoftの070-461認定資格試験トレーニング資料はIT認証試験を受ける人々の必需品です。このトレーニング資料を持っていたら、試験のために充分の準備をすることができます。

070-461 PDF DEMO:

QUESTION NO: 1
You use Microsoft SQL Server 2012 database to develop a shopping cart application.
You need to invoke a table-valued function for each row returned by a query.
Which Transact-SQL operator should you use?
A. PIVOT
B. UNPIVOT
C. CROSS APPLY
D. CROSS JOIN
Answer: C
Reference:
http://msdn.microsoft.com/en-us/library/ms175156.aspx

QUESTION NO: 2
You need to create a query that meets the following requirements:
* The query must return a list of salespeople ranked by amount of sales and organized by postal code.
* The salesperson who has the highest amount of sales must be ranked first.
Part of the correct Transact-SQL has been provided in the answer area below. Enter the code in the answer area that resolves the problem and meets the stated goals or requirements. You can add code within code that has been provided as well as below it.
Use the 'Check Syntax' button to verify your work. Any syntax or spelling errors will be reported by line and character position.
A. 1 SELECT RowNumber() OVER(PARTITION BY PostalCode ORDER BY SalesYTd DESC) AS "Ranking",
2 p.LastName, s.SalesYTD, a.PostalCode
3 FROM Sales.SalesPerson AS a
etc
On line 1 add: RowNumber
One line 1 add: PARTITION BY
ROW_NUMBER() numbers the output of a result set. More specifically, returns the sequential number of a row within a partition of a result set, starting at 1 for the first row in each partition.
SYNTAX for OVER:
OVER (
[ <PARTITION BY clause> ]
[ <ORDER BY clause> ]
[ <ROW or RANGE clause> ]
)
Example: Using the OVER clause with the ROW_NUMBER function
The following example returns the ROW_NUMBER for sales representatives based on their assigned sales quota.
SELECT ROW_NUMBER() OVER(ORDER BY SUM(SalesAmountQuota) DESC) AS RowNumber,
FirstName, LastName, CONVERT(varchar(13), SUM(SalesAmountQuota),1) AS SalesQuota FROM dbo.DimEmployee AS e INNER JOIN dbo.FactSalesQuota AS sq ON e.EmployeeKey = sq.EmployeeKey
WHERE e.SalesPersonFlag = 1 GROUP BY LastName, FirstName; Here is a partial result set.
RowNumber FirstName LastName SalesQuota
--------- --------- ------------------ -------------
1 Jillian Carson 12,198,000.00
2 Linda Mitchell 11,786,000.00
3 Michael Blythe 11,162,000.00
4 Jae Pak 10,514,000.00
B. 1 SELECT RowNumber() OVER(PARTITION BY PostalCode ORDER BY SalesYTd DESC) AS "Ranking",
2 p.LastName, s.SalesYTD, a.PostalCode
3 FROM Sales.SalesPerson AS a
etc
More specifically, returns the sequential number of a row within a partition of a result set, starting at
1 for the first row in each partition.
SYNTAX for OVER:
OVER (
[ <PARTITION BY clause> ]
[ <ORDER BY clause> ]
[ <ROW or RANGE clause> ]
)
Example: Using the OVER clause with the ROW_NUMBER function
The following example returns the ROW_NUMBER for sales representatives based on their assigned sales quota.
SELECT ROW_NUMBER() OVER(ORDER BY SUM(SalesAmountQuota) DESC) AS RowNumber,
FirstName, LastName, CONVERT(varchar(13), SUM(SalesAmountQuota),1) AS SalesQuota FROM dbo.DimEmployee AS e INNER JOIN dbo.FactSalesQuota AS sq ON e.EmployeeKey = sq.EmployeeKey
WHERE e.SalesPersonFlag = 1 GROUP BY LastName, FirstName; Here is a partial result set.
RowNumber FirstName LastName SalesQuota
--------- --------- ------------------ -------------
1 Jillian Carson 12,198,000.00
2 Linda Mitchell 11,786,000.00
3 Michael Blythe 11,162,000.00
4 Jae Pak 10,514,000.00
Answer: A
Explanation:
References:
https://docs.microsoft.com/en-us/sql/t-sql/functions/row-number-transact-sql
https://docs.microsoft.com/en-us/sql/t-sql/queries/select-over-clause-transact-sql

QUESTION NO: 3
You administer a Microsoft SQL Server database that supports a banking transaction management application.
You need to retrieve a list of account holders who live in cities that do not have a branch location.
Which Transact-SQL query or queries should you use? (Each correct answer presents a complete solution. Choose all that apply.)
A. SELECT AccountHolderID
FROM AccountHolder
WHERE CityID <> SOME (SELECT CityID FROM BranchMaster)
B. SELECT AccountHolderID
FROM AccountHolder
WHERE CityID <> ALL (SELECT CityID FROM BranchMaster)
C. SELECT AccountHolderID
FROM AccountHolder
WHERE CityID <> ANY (SELECT CityID FROM BranchMaster)
D. SELECT AccountHolderID
FROM AccountHolder
WHERE CityID NOT IN (SELECT CityID FROM BranchMaster)
Answer: B,D
Explanation:
Verified the answers as correct.

QUESTION NO: 4
You administer a Microsoft SQL Server instance that will support several databases.
You need to ensure that every new database created has a data type named postalcode that contains the same attributes.
What should you do?
A. Create a user-defined data type on the master database.
B. Create a user-defined type on the model database.
C. Create a user-defined type on the master database.
D. Create a user-defined data type on the model database.
Answer: D
Explanation:
One option is to create SQL Server user defined data types.
One trick with new databases is to create the objects in the model database, so as new databases are created the user defined data types will automatically be available.
References: https://www.mssqltips.com/sqlservertip/1628/sql-server-user-defined-data-types-rules- and-defaults/

QUESTION NO: 5
Your database contains a table named Purchases. The table includes a DATETIME column named PurchaseTime that stores the date and time each purchase is made. There is a non-clustered index on the PurchaseTime column.
The business team wants a report that displays the total number of purchases made on the current day.
You need to write a query that will return the correct results in the most efficient manner.
Which Transact-SQL query should you use?
A. SELECT COUNT(*)
FROM Purchases
WHERE PurchaseTime = GETDATE()
B. SELECT COUNT(*)
FROM Purchases
WHERE PurchaseTime >= CONVERT(DATE, GETDATE())
AND PurchaseTime < DATEADD(DAY, 1, CONVERT(DATE, GETDATE()))
C. SELECT COUNT(*)
FROM Purchases
WHERE CONVERT(VARCHAR, PurchaseTime, 112) = CONVERT(VARCHAR, GETDATE(), 112)
D. SELECT COUNT(*)
FROM Purchases
WHERE PurchaseTime = CONVERT(DATE, GETDATE())
Answer: B
Explanation:
Two answers will return the correct results (the "WHERE CONVERT..." and "WHERE ... AND ... " answers).
The correct answer for Microsoft would be the answer that is most "efficient". Anybody have a clue as to which is most efficient? In the execution plan, the one that I've selected as the correct answer is the query with the shortest duration. Also, the query answer with "WHERE CONVERT..." threw warnings in the execution plan...something about affecting CardinalityEstimate and SeekPlan.
I also found this article, which leads me to believe that I have the correct answer:
http://technet.microsoft.com/en-us/library/ms181034.aspx

MicrosoftのNetSuite NetSuite-Financial-User認定試験に合格することはきっと君の職業生涯の輝い将来に大変役に立ちます。 この問題集はHP HPE0-V25認定試験に関連する最も優秀な参考書ですから。 弊社のMicrosoftのScrum PSPO-Iソフトを購入するのを決めるとき、我々は各方面であなたに保障を提供します。 ISACA NIST-COBIT-2019 - それに、もし最初で試験を受ける場合、試験のソフトウェアのバージョンを使用することができます。 CIPS L3M3 - できるだけ100％の通過率を保証使用にしています。

Updated: May 28, 2022