がむしゃらに試験に関連する知識を勉強しているのですか。それとも、効率が良い試験070-461最新関連参考書参考書を使っているのですか。Microsoftの認証資格は最近ますます人気になっていますね。 070-461最新関連参考書問題集の更新版があったら、すぐお客様のメールボックスに送付します。どんな質問があっても、すぐ返事できます。 なぜなら、それはMicrosoftの070-461最新関連参考書認定試験に関する必要なものを含まれるからです。

MCTS 070-461 それは正確性が高くて、カバー率も広いです。

MCTS 070-461最新関連参考書 - Querying Microsoft SQL Server 2012/2014 貴方達の試験に合格させることができないと、すぐに全額で返金いたします。 無料デモはあなたに安心で購入して、購入した後1年間の無料Microsoftの070-461 資格認定試験の更新はあなたに安心で試験を準備することができます、あなたは確実に購入を休ませることができます私たちのソフトウェアを試してみてください。もちろん、我々はあなたに一番安心させるのは我々の開発する多くの受験生に合格させるMicrosoftの070-461 資格認定試験のソフトウェアです。

たくさんのひとは弊社の商品を使って、試験に順調に合格しました。そして、かれたちがリピーターになりました。NewValidDumpsが提供したMicrosoftの070-461最新関連参考書試験問題と解答が真実の試験の練習問題と解答は最高の相似性があり、一年の無料オンラインの更新のサービスがあり、100%のパス率を保証して、もし試験に合格しないと、弊社は全額で返金いたします。

Microsoft 070-461最新関連参考書 - しかも、サイトでテストデータの一部は無料です。

NewValidDumpsはIT試験問題集を提供するウエブダイトで、ここによく分かります。最もよくて最新で資料を提供いたします。こうして、君は安心で試験の準備を行ってください。弊社の資料を使って、１００％に合格を保証いたします。もし合格しないと、われは全額で返金いたします。NewValidDumpsはずっと君のために最も正確なMicrosoftの070-461最新関連参考書「Querying Microsoft SQL Server 2012/2014」試験に関する資料を提供して、君が安心に選択することができます。君はオンラインで無料な練習問題をダウンロードできて、１００％で試験に合格しましょう。

あなたはまだ何を心配しているのですか。NewValidDumpsのMicrosoftの070-461最新関連参考書トレーニング資料はあなたのニーズを満たすことができますから、躊躇わずにNewValidDumpsを選んでください。

070-461 PDF DEMO:

QUESTION NO: 1
You administer a Microsoft SQL Server instance that will support several databases.
You need to ensure that every new database created has a data type named postalcode that contains the same attributes.
What should you do?
A. Create a user-defined data type on the master database.
B. Create a user-defined type on the model database.
C. Create a user-defined type on the master database.
D. Create a user-defined data type on the model database.
Answer: D
Explanation:
One option is to create SQL Server user defined data types.
One trick with new databases is to create the objects in the model database, so as new databases are created the user defined data types will automatically be available.
References: https://www.mssqltips.com/sqlservertip/1628/sql-server-user-defined-data-types-rules- and-defaults/

QUESTION NO: 2
You need to create a query that meets the following requirements:
* The query must return a list of salespeople ranked by amount of sales and organized by postal code.
* The salesperson who has the highest amount of sales must be ranked first.
Part of the correct Transact-SQL has been provided in the answer area below. Enter the code in the answer area that resolves the problem and meets the stated goals or requirements. You can add code within code that has been provided as well as below it.
Use the 'Check Syntax' button to verify your work. Any syntax or spelling errors will be reported by line and character position.
A. 1 SELECT RowNumber() OVER(PARTITION BY PostalCode ORDER BY SalesYTd DESC) AS "Ranking",
2 p.LastName, s.SalesYTD, a.PostalCode
3 FROM Sales.SalesPerson AS a
etc
On line 1 add: RowNumber
One line 1 add: PARTITION BY
ROW_NUMBER() numbers the output of a result set. More specifically, returns the sequential number of a row within a partition of a result set, starting at 1 for the first row in each partition.
SYNTAX for OVER:
OVER (
[ <PARTITION BY clause> ]
[ <ORDER BY clause> ]
[ <ROW or RANGE clause> ]
)
Example: Using the OVER clause with the ROW_NUMBER function
The following example returns the ROW_NUMBER for sales representatives based on their assigned sales quota.
SELECT ROW_NUMBER() OVER(ORDER BY SUM(SalesAmountQuota) DESC) AS RowNumber,
FirstName, LastName, CONVERT(varchar(13), SUM(SalesAmountQuota),1) AS SalesQuota FROM dbo.DimEmployee AS e INNER JOIN dbo.FactSalesQuota AS sq ON e.EmployeeKey = sq.EmployeeKey
WHERE e.SalesPersonFlag = 1 GROUP BY LastName, FirstName; Here is a partial result set.
RowNumber FirstName LastName SalesQuota
--------- --------- ------------------ -------------
1 Jillian Carson 12,198,000.00
2 Linda Mitchell 11,786,000.00
3 Michael Blythe 11,162,000.00
4 Jae Pak 10,514,000.00
B. 1 SELECT RowNumber() OVER(PARTITION BY PostalCode ORDER BY SalesYTd DESC) AS "Ranking",
2 p.LastName, s.SalesYTD, a.PostalCode
3 FROM Sales.SalesPerson AS a
etc
More specifically, returns the sequential number of a row within a partition of a result set, starting at
1 for the first row in each partition.
SYNTAX for OVER:
OVER (
[ <PARTITION BY clause> ]
[ <ORDER BY clause> ]
[ <ROW or RANGE clause> ]
)
Example: Using the OVER clause with the ROW_NUMBER function
The following example returns the ROW_NUMBER for sales representatives based on their assigned sales quota.
SELECT ROW_NUMBER() OVER(ORDER BY SUM(SalesAmountQuota) DESC) AS RowNumber,
FirstName, LastName, CONVERT(varchar(13), SUM(SalesAmountQuota),1) AS SalesQuota FROM dbo.DimEmployee AS e INNER JOIN dbo.FactSalesQuota AS sq ON e.EmployeeKey = sq.EmployeeKey
WHERE e.SalesPersonFlag = 1 GROUP BY LastName, FirstName; Here is a partial result set.
RowNumber FirstName LastName SalesQuota
--------- --------- ------------------ -------------
1 Jillian Carson 12,198,000.00
2 Linda Mitchell 11,786,000.00
3 Michael Blythe 11,162,000.00
4 Jae Pak 10,514,000.00
Answer: A
Explanation:
References:
https://docs.microsoft.com/en-us/sql/t-sql/functions/row-number-transact-sql
https://docs.microsoft.com/en-us/sql/t-sql/queries/select-over-clause-transact-sql

QUESTION NO: 3
You use Microsoft SQL Server 2012 database to develop a shopping cart application.
You need to invoke a table-valued function for each row returned by a query.
Which Transact-SQL operator should you use?
A. PIVOT
B. UNPIVOT
C. CROSS APPLY
D. CROSS JOIN
Answer: C
Reference:
http://msdn.microsoft.com/en-us/library/ms175156.aspx

QUESTION NO: 4
You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid- year marks for students. The table has marks obtained by 50 students for various subjects.
You need to ensure that the following requirements are met:
* Students must be ranked based on their average marks.
* If one or more students have the same average, the same rank must be given to these students.
* Consecutive ranks must be skipped when the same rank is assigned.
Which Transact-SQL query should you use?
A. SELECT Id, Name, Marks,
DENSE_RANK() OVER(ORDER BY Marks DESC) AS Rank
FROM StudentMarks
B. SELECT StudentCode as Code,
NTILE(2) OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
C. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
D. SELECT StudentCode as Code,
RANK() OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
E. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
F. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANXO OVER(PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
G. SELECT StudentCode as Code,
DENSE_RANK() OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
H. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
Answer: D
Reference:
http://msdn.microsoft.com/en-us/library/ms189798.aspx

QUESTION NO: 5
You administer a Microsoft SQL Server database that supports a banking transaction management application.
You need to retrieve a list of account holders who live in cities that do not have a branch location.
Which Transact-SQL query or queries should you use? (Each correct answer presents a complete solution. Choose all that apply.)
A. SELECT AccountHolderID
FROM AccountHolder
WHERE CityID <> SOME (SELECT CityID FROM BranchMaster)
B. SELECT AccountHolderID
FROM AccountHolder
WHERE CityID <> ALL (SELECT CityID FROM BranchMaster)
C. SELECT AccountHolderID
FROM AccountHolder
WHERE CityID <> ANY (SELECT CityID FROM BranchMaster)
D. SELECT AccountHolderID
FROM AccountHolder
WHERE CityID NOT IN (SELECT CityID FROM BranchMaster)
Answer: B,D
Explanation:
Verified the answers as correct.

Microsoft Cisco 300-425「Querying Microsoft SQL Server 2012/2014」認証試験に合格することが簡単ではなくて、Microsoft Cisco 300-425証明書は君にとってはIT業界に入るの一つの手づるになるかもしれません。 MicrosoftのMicrosoft SC-200J試験に受かるのは実際にそんなに難しいことではないです。 Salesforce Sales-Cloud-Consultant-JPN - 今の社会の中で、ネット上で訓練は普及して、弊社は試験問題集を提供する多くのネットの一つでございます。 MicrosoftのMicrosoft DP-300J試験に受かるのはIT職員の皆さんの目標です。 CompTIA PT0-002 - 試験問題と解答に関する質問があるなら、当社は直後に解決方法を差し上げます。

Updated: May 28, 2022