070-461テスト難易度 資格取得

現在IT技術会社に通勤しているあなたは、Microsoftの070-461テスト難易度試験認定を取得しましたか?070-461テスト難易度試験認定は給料の増加とジョブのプロモーションに役立ちます。短時間で070-461テスト難易度試験に一発合格したいなら、我々社のMicrosoftの070-461テスト難易度資料を参考しましょう。また、070-461テスト難易度問題集に疑問があると、メールで問い合わせてください。 NewValidDumpsの商品はIT業界の専門家が自分の豊かな知識と経験を利用して認証試験に対して研究出たので品質がいいの試験の資料でございます。受験者がNewValidDumpsを選択したら高度専門の試験に100%合格することが問題にならないと保証いたします。 だから、我々社は力の限りで弊社のMicrosoft 070-461テスト難易度試験資料を改善し、改革の変更に応じて更新します。

MCTS 070-461 NewValidDumpsには専門的なエリート団体があります。

MCTS 070-461テスト難易度 - Querying Microsoft SQL Server 2012/2014 当社の製品を利用したら、一年間の無料更新サービスを提供します。 試験の目標が変わる限り、あるいは我々の勉強資料が変わる限り、すぐに更新して差し上げます。あなたのニーズをよく知っていていますから、あなたに試験に合格する自信を与えます。

順調にIT認定試験に合格したいなら、NewValidDumpsはあなたの唯一の選択です。NewValidDumpsに提供されている資料はIT認定試験に対して10年過ぎの経験を持っているプロフェッショナルによって研究と実践を通じて作成し出されたものです。NewValidDumpsは最新かつ最も正確な試験070-461テスト難易度問題集を用意しておきます。

Microsoft 070-461テスト難易度 - あなたの能力は彼らうより弱いですか。

IT技術の急速な発展につれて、IT認証試験の問題は常に変更されています。したがって、NewValidDumpsの070-461テスト難易度問題集も絶えずに更新されています。それに、NewValidDumpsの教材を購入すれば、NewValidDumpsは一年間の無料アップデート・サービスを提供してあげます。問題が更新される限り、NewValidDumpsは直ちに最新版の070-461テスト難易度資料を送ってあげます。そうすると、あなたがいつでも最新バージョンの資料を持っていることが保証されます。NewValidDumpsはあなたが試験に合格するのを助けることができるだけでなく、あなたは最新の知識を学ぶのを助けることもできます。このような素晴らしい資料をぜひ見逃さないでください。

それはもちろんNewValidDumpsの070-461テスト難易度問題集ですよ。070-461テスト難易度試験の準備をするとき、がむしゃらにITに関連する知識を学ぶのは望ましくない勉強法です。

070-461 PDF DEMO:

QUESTION NO: 1
You administer a Microsoft SQL Server database that supports a banking transaction management application.
You need to retrieve a list of account holders who live in cities that do not have a branch location.
Which Transact-SQL query or queries should you use? (Each correct answer presents a complete solution. Choose all that apply.)
A. SELECT AccountHolderID
FROM AccountHolder
WHERE CityID <> SOME (SELECT CityID FROM BranchMaster)
B. SELECT AccountHolderID
FROM AccountHolder
WHERE CityID <> ALL (SELECT CityID FROM BranchMaster)
C. SELECT AccountHolderID
FROM AccountHolder
WHERE CityID <> ANY (SELECT CityID FROM BranchMaster)
D. SELECT AccountHolderID
FROM AccountHolder
WHERE CityID NOT IN (SELECT CityID FROM BranchMaster)
Answer: B,D
Explanation:
Verified the answers as correct.

QUESTION NO: 2
You use Microsoft SQL Server 2012 database to develop a shopping cart application.
You need to invoke a table-valued function for each row returned by a query.
Which Transact-SQL operator should you use?
A. PIVOT
B. UNPIVOT
C. CROSS APPLY
D. CROSS JOIN
Answer: C
Reference:
http://msdn.microsoft.com/en-us/library/ms175156.aspx

QUESTION NO: 3
Your database contains a table named Purchases. The table includes a DATETIME column named PurchaseTime that stores the date and time each purchase is made. There is a non-clustered index on the PurchaseTime column.
The business team wants a report that displays the total number of purchases made on the current day.
You need to write a query that will return the correct results in the most efficient manner.
Which Transact-SQL query should you use?
A. SELECT COUNT(*)
FROM Purchases
WHERE PurchaseTime = GETDATE()
B. SELECT COUNT(*)
FROM Purchases
WHERE PurchaseTime >= CONVERT(DATE, GETDATE())
AND PurchaseTime < DATEADD(DAY, 1, CONVERT(DATE, GETDATE()))
C. SELECT COUNT(*)
FROM Purchases
WHERE CONVERT(VARCHAR, PurchaseTime, 112) = CONVERT(VARCHAR, GETDATE(), 112)
D. SELECT COUNT(*)
FROM Purchases
WHERE PurchaseTime = CONVERT(DATE, GETDATE())
Answer: B
Explanation:
Two answers will return the correct results (the "WHERE CONVERT..." and "WHERE ... AND ... " answers).
The correct answer for Microsoft would be the answer that is most "efficient". Anybody have a clue as to which is most efficient? In the execution plan, the one that I've selected as the correct answer is the query with the shortest duration. Also, the query answer with "WHERE CONVERT..." threw warnings in the execution plan...something about affecting CardinalityEstimate and SeekPlan.
I also found this article, which leads me to believe that I have the correct answer:
http://technet.microsoft.com/en-us/library/ms181034.aspx

QUESTION NO: 4
You need to create a query that meets the following requirements:
* The query must return a list of salespeople ranked by amount of sales and organized by postal code.
* The salesperson who has the highest amount of sales must be ranked first.
Part of the correct Transact-SQL has been provided in the answer area below. Enter the code in the answer area that resolves the problem and meets the stated goals or requirements. You can add code within code that has been provided as well as below it.
Use the 'Check Syntax' button to verify your work. Any syntax or spelling errors will be reported by line and character position.
A. 1 SELECT RowNumber() OVER(PARTITION BY PostalCode ORDER BY SalesYTd DESC) AS "Ranking",
2 p.LastName, s.SalesYTD, a.PostalCode
3 FROM Sales.SalesPerson AS a
etc
On line 1 add: RowNumber
One line 1 add: PARTITION BY
ROW_NUMBER() numbers the output of a result set. More specifically, returns the sequential number of a row within a partition of a result set, starting at 1 for the first row in each partition.
SYNTAX for OVER:
OVER (
[ <PARTITION BY clause> ]
[ <ORDER BY clause> ]
[ <ROW or RANGE clause> ]
)
Example: Using the OVER clause with the ROW_NUMBER function
The following example returns the ROW_NUMBER for sales representatives based on their assigned sales quota.
SELECT ROW_NUMBER() OVER(ORDER BY SUM(SalesAmountQuota) DESC) AS RowNumber,
FirstName, LastName, CONVERT(varchar(13), SUM(SalesAmountQuota),1) AS SalesQuota FROM dbo.DimEmployee AS e INNER JOIN dbo.FactSalesQuota AS sq ON e.EmployeeKey = sq.EmployeeKey
WHERE e.SalesPersonFlag = 1 GROUP BY LastName, FirstName; Here is a partial result set.
RowNumber FirstName LastName SalesQuota
--------- --------- ------------------ -------------
1 Jillian Carson 12,198,000.00
2 Linda Mitchell 11,786,000.00
3 Michael Blythe 11,162,000.00
4 Jae Pak 10,514,000.00
B. 1 SELECT RowNumber() OVER(PARTITION BY PostalCode ORDER BY SalesYTd DESC) AS "Ranking",
2 p.LastName, s.SalesYTD, a.PostalCode
3 FROM Sales.SalesPerson AS a
etc
More specifically, returns the sequential number of a row within a partition of a result set, starting at
1 for the first row in each partition.
SYNTAX for OVER:
OVER (
[ <PARTITION BY clause> ]
[ <ORDER BY clause> ]
[ <ROW or RANGE clause> ]
)
Example: Using the OVER clause with the ROW_NUMBER function
The following example returns the ROW_NUMBER for sales representatives based on their assigned sales quota.
SELECT ROW_NUMBER() OVER(ORDER BY SUM(SalesAmountQuota) DESC) AS RowNumber,
FirstName, LastName, CONVERT(varchar(13), SUM(SalesAmountQuota),1) AS SalesQuota FROM dbo.DimEmployee AS e INNER JOIN dbo.FactSalesQuota AS sq ON e.EmployeeKey = sq.EmployeeKey
WHERE e.SalesPersonFlag = 1 GROUP BY LastName, FirstName; Here is a partial result set.
RowNumber FirstName LastName SalesQuota
--------- --------- ------------------ -------------
1 Jillian Carson 12,198,000.00
2 Linda Mitchell 11,786,000.00
3 Michael Blythe 11,162,000.00
4 Jae Pak 10,514,000.00
Answer: A
Explanation:
References:
https://docs.microsoft.com/en-us/sql/t-sql/functions/row-number-transact-sql
https://docs.microsoft.com/en-us/sql/t-sql/queries/select-over-clause-transact-sql

QUESTION NO: 5
You administer a Microsoft SQL Server 2012 database named ContosoDb. Tables are defined as shown in the exhibit. (Click the Exhibit button.)
You need to display rows from the Orders table for the Customers row having the CustomerId value set to 1 in the following XML format:
<row OrderId="1" OrderDate="2000-01-01T00:00:00" Amount="3400.00" Name="Customer A"
Country="Australia" />
<row OrderId="2" OrderDate="2001-01-01T00:00:00" Amount="4300.00" Name="Customer A"
Country="Australia" /> Which Transact-SQL query should you use?
A. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML RAW
B. SELECT Name AS 'Customers/Name', Country AS 'Customers/Country', OrderId, OrderDate,
Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId = 1 FOR XML PATH ('Customers')
C. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId - Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML AUTO, ELEMENTS
D. SELECT Name, Country, OrderId, OrderDate, Amount
FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML AUTO, ELEMENTS
E. SELECT Name, Country, OrderId, OrderDate, Amount
FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML AUTO
F. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML AUTO
G. SELECT Name AS '@Name', Country AS '@Country', OrderId, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML PATH ('Customers')
H. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML RAW, ELEMENTS
Answer: A

NewValidDumpsのSAP C-DS-43問題集は多くの受験生に検証されたものですから、高い成功率を保証できます。 MicrosoftのCompTIA SY0-601問題集はCompTIA SY0-601に関する問題をほとんど含まれます。 NewValidDumpsのITエリートたちは彼らの専門的な目で、最新的なMicrosoftのMicrosoft AI-102試験トレーニング資料に注目していて、うちのMicrosoftのMicrosoft AI-102問題集の高い正確性を保証するのです。 Fortinet NSE5_FAZ-7.2 - NewValidDumpsを選ぶなら、成功を選ぶのに等しいです。 MicrosoftのSalesforce CRT-403認定試験に合格することはきっと君の職業生涯の輝い将来に大変役に立ちます。

Updated: May 28, 2022

070-461テスト難易度、070-461受験料 - Microsoft 070-461予想試験

PDF問題と解答

試験コード:070-461
試験名称:Querying Microsoft SQL Server 2012/2014
最近更新時間:2024-05-18
問題と解答:全 252
Microsoft 070-461 資料的中率

  ダウンロード


 

模擬試験

試験コード:070-461
試験名称:Querying Microsoft SQL Server 2012/2014
最近更新時間:2024-05-18
問題と解答:全 252
Microsoft 070-461 クラムメディア

  ダウンロード


 

オンライン版

試験コード:070-461
試験名称:Querying Microsoft SQL Server 2012/2014
最近更新時間:2024-05-18
問題と解答:全 252
Microsoft 070-461 模擬体験

  ダウンロード


 

070-461 試験情報