この参考書は短い時間で試験に十分に準備させ、そして楽に試験に合格させます。試験のためにあまりの時間と精力を無駄にしたくないなら、NewValidDumpsの70-461最新対策問題問題集は間違いなくあなたに最もふさわしい選択です。この資料を使用すると、あなたの学習効率を向上させ、多くの時間を節約することができます。 NewValidDumpsのMicrosoftの70-461最新対策問題試験トレーニング資料は試験問題と解答を含まれて、豊富な経験を持っているIT業種の専門家が長年の研究を通じて作成したものです。その権威性は言うまでもありません。 Microsoftの70-461最新対策問題認証資格を取得すると、あなたは大きなヘルプを得ることができます。

MCSA 70-461 我々のデモから感じられます。

現在IT技術会社に通勤しているあなたは、Microsoftの70-461 - Querying Microsoft SQL Server 2012/2014最新対策問題試験認定を取得しましたか？70-461 - Querying Microsoft SQL Server 2012/2014最新対策問題試験認定は給料の増加とジョブのプロモーションに役立ちます。 Microsoftの70-461 認定資格試験にリラクスで合格するのも可能性があります。我々NewValidDumpsの提供するMicrosoftの70-461 認定資格試験のソフトを利用した多くのお客様はこのような感じがあります。

だから、我々社は力の限りで弊社のMicrosoft　70-461最新対策問題試験資料を改善し、改革の変更に応じて更新します。あなたはいつまでも最新版の問題集を使用できるために、ご購入の一年間で無料の更新を提供します。人によって目標が違いますが、あなたにMicrosoft　70-461最新対策問題試験に順調に合格できるのは我々の共同の目標です。

Microsoft 70-461最新対策問題 - それをもって、試験は問題になりませんよ。

NewValidDumpsの70-461最新対策問題問題集は多くの受験生に検証されたものですから、高い成功率を保証できます。もしこの問題集を利用してからやはり試験に不合格になってしまえば、NewValidDumpsは全額で返金することができます。あるいは、無料で試験70-461最新対策問題問題集を更新してあげるのを選択することもできます。こんな保障がありますから、心配する必要は全然ないですよ。

NewValidDumpsはとても人気がありますから、それを選ばない理由はないです。もちろん、完璧なトレーニング資料を差し上げましたが、もしあなたに向いていないのなら無用になりますから、NewValidDumpsを利用する前に、一部の問題と解答を無料にダウンロードしてみることができます。

70-461 PDF DEMO:

QUESTION NO: 1
You administer a Microsoft SQL Server 2012 database named ContosoDb. Tables are defined as shown in the exhibit. (Click the Exhibit button.)
You need to display rows from the Orders table for the Customers row having the CustomerId value set to 1 in the following XML format:
<row OrderId="1" OrderDate="2000-01-01T00:00:00" Amount="3400.00" Name="Customer A"
Country="Australia" />
<row OrderId="2" OrderDate="2001-01-01T00:00:00" Amount="4300.00" Name="Customer A"
Country="Australia" /> Which Transact-SQL query should you use?
A. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML RAW
B. SELECT Name AS 'Customers/Name', Country AS 'Customers/Country', OrderId, OrderDate,
Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId = 1 FOR XML PATH ('Customers')
C. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId - Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML AUTO, ELEMENTS
D. SELECT Name, Country, OrderId, OrderDate, Amount
FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML AUTO, ELEMENTS
E. SELECT Name, Country, OrderId, OrderDate, Amount
FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML AUTO
F. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML AUTO
G. SELECT Name AS '@Name', Country AS '@Country', OrderId, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML PATH ('Customers')
H. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML RAW, ELEMENTS
Answer: A

QUESTION NO: 2
Your database contains a table named Purchases. The table includes a DATETIME column named PurchaseTime that stores the date and time each purchase is made. There is a non-clustered index on the PurchaseTime column.
The business team wants a report that displays the total number of purchases made on the current day.
You need to write a query that will return the correct results in the most efficient manner.
Which Transact-SQL query should you use?
A. SELECT COUNT(*)
FROM Purchases
WHERE PurchaseTime = GETDATE()
B. SELECT COUNT(*)
FROM Purchases
WHERE PurchaseTime >= CONVERT(DATE, GETDATE())
AND PurchaseTime < DATEADD(DAY, 1, CONVERT(DATE, GETDATE()))
C. SELECT COUNT(*)
FROM Purchases
WHERE CONVERT(VARCHAR, PurchaseTime, 112) = CONVERT(VARCHAR, GETDATE(), 112)
D. SELECT COUNT(*)
FROM Purchases
WHERE PurchaseTime = CONVERT(DATE, GETDATE())
Answer: B
Explanation:
Two answers will return the correct results (the "WHERE CONVERT..." and "WHERE ... AND ... " answers).
The correct answer for Microsoft would be the answer that is most "efficient". Anybody have a clue as to which is most efficient? In the execution plan, the one that I've selected as the correct answer is the query with the shortest duration. Also, the query answer with "WHERE CONVERT..." threw warnings in the execution plan...something about affecting CardinalityEstimate and SeekPlan.
I also found this article, which leads me to believe that I have the correct answer:
http://technet.microsoft.com/en-us/library/ms181034.aspx

QUESTION NO: 3
You are the administrator for a heavily-used OLTP Microsoft SQL Server database.
You are troubleshooting performance issues seen when using stored procedures in the database. The database stores millions of orders across thousands of customers. Some of the customers have large numbers of orders, while others have only one order. You update the statistics and perform defragmentation of all tables and indexes, but two stored procedures still have issues when accessing data.
p_GetCustomer accepts @companyID as a parameter. From the results of profiling, you know that 90 percent of the calls use the @companyid value of 5, while the other 10 percent of calls are evenly distributed across another 10000 values. While viewing the execution plan, you discover that a non- clustered index seek is used.
p_GetShipDate accepts @orderID as a parameter and returns the ship date for that order. You discover that the execution plan is performing a scan on a non-clustered index that has orderID as the index key.
You need to add appropriate query hints to each stored procedure to improve the performance.
What should you do? To answer, drag the appropriate procedures to the correct hints. Each procedure may be used once, more than once, or not at all. You may need to drag the split bar between panes or scroll to view content.
Answer:
Explanation:
Box 1: Optimize FOR..
OPTIMIZE FOR ( @variable_name { UNKNOWN | = literal_constant } [ , ...n ] ) Instructs the query optimizer to use a particular value for a local variable when the query is compiled and optimized. The value is used only during query optimization, and not during query execution.
Box 2: FORCESEEK
FORCESEEK [ (index_value(index_column_name [ ,... n ] )) ]
Specifies that the query optimizer use only an index seek operation as the access path to the data in the table or view.
References:
https://docs.microsoft.com/en-us/sql/t-sql/queries/hints-transact-sql-query?view=sql-server-2017
https://docs.microsoft.com/en-us/sql/t-sql/queries/hints-transact-sql-table?view=sql-server-2017

QUESTION NO: 4
You administer a Microsoft SQL Server database that supports a banking transaction management application.
You need to retrieve a list of account holders who live in cities that do not have a branch location.
Which Transact-SQL query or queries should you use? (Each correct answer presents a complete solution. Choose all that apply.)
A. SELECT AccountHolderID
FROM AccountHolder
WHERE CityID <> SOME (SELECT CityID FROM BranchMaster)
B. SELECT AccountHolderID
FROM AccountHolder
WHERE CityID <> ALL (SELECT CityID FROM BranchMaster)
C. SELECT AccountHolderID
FROM AccountHolder
WHERE CityID <> ANY (SELECT CityID FROM BranchMaster)
D. SELECT AccountHolderID
FROM AccountHolder
WHERE CityID NOT IN (SELECT CityID FROM BranchMaster)
Answer: B,D
Explanation:
Verified the answers as correct.

QUESTION NO: 5
You use Microsoft SQL Server 2012 database to develop a shopping cart application.
You need to invoke a table-valued function for each row returned by a query.
Which Transact-SQL operator should you use?
A. PIVOT
B. UNPIVOT
C. CROSS APPLY
D. CROSS JOIN
Answer: C
Reference:
http://msdn.microsoft.com/en-us/library/ms175156.aspx

NewValidDumpsのITエリートたちは彼らの専門的な目で、最新的なMicrosoftのPECB ISO-IEC-27001-Lead-Auditor試験トレーニング資料に注目していて、うちのMicrosoftのPECB ISO-IEC-27001-Lead-Auditor問題集の高い正確性を保証するのです。 WGU Secure-Software-Design - それはNewValidDumpsが提供する問題資料は絶対あなたが試験に受かることを助けられるからです。 MicrosoftのUSGBC LEED-AP-O-M認定試験に合格することはきっと君の職業生涯の輝い将来に大変役に立ちます。 OMG OMG-OCUP2-FOUND100 - 当社の製品は、すべての可能性のある問題を試させられます。 購入した前の無料の試み、購入するときのお支払いへの保障、購入した一年間の無料更新MicrosoftのIBM C1000-058試験に失敗した全額での返金…これらは我々のお客様への承諾です。

Updated: May 28, 2022