それはいくつかの理由があります。第一、NewValidDumpsは受験生の要求をよく知っています。しかも、他のどのサイトよりも良いサービスを提供します。 NewValidDumpsが提供したMicrosoftの70-461日本語的中対策トレーニング資料を利用したら、Microsoftの70-461日本語的中対策認定試験に受かることはたやすくなります。NewValidDumpsがデザインしたトレーニングツールはあなたが一回で試験に合格することにヘルプを差し上げられます。 時には、成功と失敗の距離は非常に短いです。

MCSA 70-461 それでも恐れることはありません。

IT認定試験の中でどんな試験を受けても、NewValidDumpsの70-461 - Querying Microsoft SQL Server 2012/2014日本語的中対策試験参考資料はあなたに大きなヘルプを与えることができます。 皆さんからいろいろな好評をもらいました。しかも、NewValidDumpsは当面の市場で皆さんが一番信頼できるサイトです。

その中で、70-461日本語的中対策認定試験は最も重要な一つです。では、この試験に合格するためにどのように試験の準備をしているのですか。がむしゃらに試験に関連する知識を勉強しているのですか。

Microsoft 70-461日本語的中対策 - それは正確性が高くて、カバー率も広いです。

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70-461 PDF DEMO:

QUESTION NO: 1
You have an XML schema collection named Sales.InvoiceSchema.
You need to declare a variable of the XML type named invoice. The solution must ensure that the invoice is validated by using Sales.InvoiceSchema.
The solution must ensure that the invoice variable is validated by using Sales.InvoiceSchema schema.
Provide the correct code in the answer area.
Answer:
DECLARE @invoice XML(Sales.InvoiceSchema)

QUESTION NO: 2
You are the administrator for a heavily-used OLTP Microsoft SQL Server database.
You are troubleshooting performance issues seen when using stored procedures in the database. The database stores millions of orders across thousands of customers. Some of the customers have large numbers of orders, while others have only one order. You update the statistics and perform defragmentation of all tables and indexes, but two stored procedures still have issues when accessing data.
p_GetCustomer accepts @companyID as a parameter. From the results of profiling, you know that 90 percent of the calls use the @companyid value of 5, while the other 10 percent of calls are evenly distributed across another 10000 values. While viewing the execution plan, you discover that a non- clustered index seek is used.
p_GetShipDate accepts @orderID as a parameter and returns the ship date for that order. You discover that the execution plan is performing a scan on a non-clustered index that has orderID as the index key.
You need to add appropriate query hints to each stored procedure to improve the performance.
What should you do? To answer, drag the appropriate procedures to the correct hints. Each procedure may be used once, more than once, or not at all. You may need to drag the split bar between panes or scroll to view content.
Answer:
Explanation:
Box 1: Optimize FOR..
OPTIMIZE FOR ( @variable_name { UNKNOWN | = literal_constant } [ , ...n ] ) Instructs the query optimizer to use a particular value for a local variable when the query is compiled and optimized. The value is used only during query optimization, and not during query execution.
Box 2: FORCESEEK
FORCESEEK [ (index_value(index_column_name [ ,... n ] )) ]
Specifies that the query optimizer use only an index seek operation as the access path to the data in the table or view.
References:
https://docs.microsoft.com/en-us/sql/t-sql/queries/hints-transact-sql-query?view=sql-server-2017
https://docs.microsoft.com/en-us/sql/t-sql/queries/hints-transact-sql-table?view=sql-server-2017

QUESTION NO: 3
You administer a Microsoft SQL Server 2012 database named ContosoDb. Tables are defined as shown in the exhibit. (Click the Exhibit button.)
You need to display rows from the Orders table for the Customers row having the CustomerId value set to 1 in the following XML format:
<row OrderId="1" OrderDate="2000-01-01T00:00:00" Amount="3400.00" Name="Customer A"
Country="Australia" />
<row OrderId="2" OrderDate="2001-01-01T00:00:00" Amount="4300.00" Name="Customer A"
Country="Australia" /> Which Transact-SQL query should you use?
A. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML RAW
B. SELECT Name AS 'Customers/Name', Country AS 'Customers/Country', OrderId, OrderDate,
Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId = 1 FOR XML PATH ('Customers')
C. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId - Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML AUTO, ELEMENTS
D. SELECT Name, Country, OrderId, OrderDate, Amount
FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML AUTO, ELEMENTS
E. SELECT Name, Country, OrderId, OrderDate, Amount
FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML AUTO
F. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML AUTO
G. SELECT Name AS '@Name', Country AS '@Country', OrderId, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML PATH ('Customers')
H. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML RAW, ELEMENTS
Answer: A

QUESTION NO: 4
You have a database that contains the tables shown in the exhibit. (Click the Exhibit button.)
You need to create a view named uv_CustomerFullName to meet the following requirements:
* The code must NOT include object delimiters.
* The view must be created in the Sales schema.
* Columns must only be referenced by using one-part names.
* The view must return the first name and the last name of all customers.
* The view must prevent the underlying structure of the customer table from being changed.
* The view must be able to resolve all referenced objects, regardless of the user's default schema.
Which code segment should you use?
To answer, type the correct code in the answer area.
A. CREATE VIEW Sales.uv_CustomerFullName
WITH SCHEMABINDING
AS
SELECT FirstName, LastName
B. CREATE VIEW Sales.uv_CustomerFullName
WITH SCHEMABINDING
AS
SELECT FirstName, LastName
FROM Sales.Customers
Answer: B
Reference:
http://msdn.microsoft.com/en-us/library/ms187956.aspx

QUESTION NO: 5
Your database contains a table named Purchases. The table includes a DATETIME column named PurchaseTime that stores the date and time each purchase is made. There is a non-clustered index on the PurchaseTime column.
The business team wants a report that displays the total number of purchases made on the current day.
You need to write a query that will return the correct results in the most efficient manner.
Which Transact-SQL query should you use?
A. SELECT COUNT(*)
FROM Purchases
WHERE PurchaseTime = GETDATE()
B. SELECT COUNT(*)
FROM Purchases
WHERE PurchaseTime >= CONVERT(DATE, GETDATE())
AND PurchaseTime < DATEADD(DAY, 1, CONVERT(DATE, GETDATE()))
C. SELECT COUNT(*)
FROM Purchases
WHERE CONVERT(VARCHAR, PurchaseTime, 112) = CONVERT(VARCHAR, GETDATE(), 112)
D. SELECT COUNT(*)
FROM Purchases
WHERE PurchaseTime = CONVERT(DATE, GETDATE())
Answer: B
Explanation:
Two answers will return the correct results (the "WHERE CONVERT..." and "WHERE ... AND ... " answers).
The correct answer for Microsoft would be the answer that is most "efficient". Anybody have a clue as to which is most efficient? In the execution plan, the one that I've selected as the correct answer is the query with the shortest duration. Also, the query answer with "WHERE CONVERT..." threw warnings in the execution plan...something about affecting CardinalityEstimate and SeekPlan.
I also found this article, which leads me to believe that I have the correct answer:
http://technet.microsoft.com/en-us/library/ms181034.aspx

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Updated: May 28, 2022