そして、Microsoftはお客様にディスカウントコードを提供でき、70-461復習過去問復習教材をより安く購入できます。70-461復習過去問試験資格証明書を取得することは難しいです。でも、Microsoft　70-461復習過去問復習教材を選ばれば、試験に合格することは簡単です。 我々もオンライン版とソフト版を提供します。すべては豊富な内容があって各自のメリットを持っています。 この試験に合格すれば君の専門知識がとても強いを証明し得ます。

それはNewValidDumpsの70-461復習過去問問題集です。

MCSA 70-461復習過去問 - Querying Microsoft SQL Server 2012/2014 私たちは君がITエリートになるのに頑張ります。 一回だけでMicrosoftの70-461 模擬体験試験に合格したい？NewValidDumpsは君の欲求を満たすために存在するのです。NewValidDumpsは君にとってベストな選択になります。

NewValidDumpsでは、私たちは君のすべての夢を叶えさせて、君の最も早い時間でMicrosoftの70-461復習過去問認定試験に合格するということを保証します。NewValidDumpsのMicrosoftの70-461復習過去問試験トレーニング資料は豊富な経験を持っているIT専門家が研究したもので、問題と解答が緊密に結んでいるものです。NewValidDumpsを選ぶなら、絶対に後悔させません。

Microsoft 70-461復習過去問 - 数年以来の試験問題集を研究しています。

現在IT技術会社に通勤しているあなたは、Microsoftの70-461復習過去問試験認定を取得しましたか？70-461復習過去問試験認定は給料の増加とジョブのプロモーションに役立ちます。短時間で70-461復習過去問試験に一発合格したいなら、我々社のMicrosoftの70-461復習過去問資料を参考しましょう。また、70-461復習過去問問題集に疑問があると、メールで問い合わせてください。

弊社はお客様の皆様の利益を保証するために、あなたに高いクオリティのサービスを提供できて努力しています。今まで、弊社のNewValidDumpsの70-461復習過去問問題集はそのスローガンに沿って協力します。

70-461 PDF DEMO:

QUESTION NO: 1
You use Microsoft SQL Server 2012 database to develop a shopping cart application.
You need to invoke a table-valued function for each row returned by a query.
Which Transact-SQL operator should you use?
A. PIVOT
B. UNPIVOT
C. CROSS APPLY
D. CROSS JOIN
Answer: C
Reference:
http://msdn.microsoft.com/en-us/library/ms175156.aspx

QUESTION NO: 2
You administer a Microsoft SQL Server database that supports a banking transaction management application.
You need to retrieve a list of account holders who live in cities that do not have a branch location.
Which Transact-SQL query or queries should you use? (Each correct answer presents a complete solution. Choose all that apply.)
A. SELECT AccountHolderID
FROM AccountHolder
WHERE CityID <> SOME (SELECT CityID FROM BranchMaster)
B. SELECT AccountHolderID
FROM AccountHolder
WHERE CityID <> ALL (SELECT CityID FROM BranchMaster)
C. SELECT AccountHolderID
FROM AccountHolder
WHERE CityID <> ANY (SELECT CityID FROM BranchMaster)
D. SELECT AccountHolderID
FROM AccountHolder
WHERE CityID NOT IN (SELECT CityID FROM BranchMaster)
Answer: B,D
Explanation:
Verified the answers as correct.

QUESTION NO: 3
You need to create a query that meets the following requirements:
* The query must return a list of salespeople ranked by amount of sales and organized by postal code.
* The salesperson who has the highest amount of sales must be ranked first.
Part of the correct Transact-SQL has been provided in the answer area below. Enter the code in the answer area that resolves the problem and meets the stated goals or requirements. You can add code within code that has been provided as well as below it.
Use the 'Check Syntax' button to verify your work. Any syntax or spelling errors will be reported by line and character position.
A. 1 SELECT RowNumber() OVER(PARTITION BY PostalCode ORDER BY SalesYTd DESC) AS "Ranking",
2 p.LastName, s.SalesYTD, a.PostalCode
3 FROM Sales.SalesPerson AS a
etc
On line 1 add: RowNumber
One line 1 add: PARTITION BY
ROW_NUMBER() numbers the output of a result set. More specifically, returns the sequential number of a row within a partition of a result set, starting at 1 for the first row in each partition.
SYNTAX for OVER:
OVER (
[ <PARTITION BY clause> ]
[ <ORDER BY clause> ]
[ <ROW or RANGE clause> ]
)
Example: Using the OVER clause with the ROW_NUMBER function
The following example returns the ROW_NUMBER for sales representatives based on their assigned sales quota.
SELECT ROW_NUMBER() OVER(ORDER BY SUM(SalesAmountQuota) DESC) AS RowNumber,
FirstName, LastName, CONVERT(varchar(13), SUM(SalesAmountQuota),1) AS SalesQuota FROM dbo.DimEmployee AS e INNER JOIN dbo.FactSalesQuota AS sq ON e.EmployeeKey = sq.EmployeeKey
WHERE e.SalesPersonFlag = 1 GROUP BY LastName, FirstName; Here is a partial result set.
RowNumber FirstName LastName SalesQuota
--------- --------- ------------------ -------------
1 Jillian Carson 12,198,000.00
2 Linda Mitchell 11,786,000.00
3 Michael Blythe 11,162,000.00
4 Jae Pak 10,514,000.00
B. 1 SELECT RowNumber() OVER(PARTITION BY PostalCode ORDER BY SalesYTd DESC) AS "Ranking",
2 p.LastName, s.SalesYTD, a.PostalCode
3 FROM Sales.SalesPerson AS a
etc
More specifically, returns the sequential number of a row within a partition of a result set, starting at
1 for the first row in each partition.
SYNTAX for OVER:
OVER (
[ <PARTITION BY clause> ]
[ <ORDER BY clause> ]
[ <ROW or RANGE clause> ]
)
Example: Using the OVER clause with the ROW_NUMBER function
The following example returns the ROW_NUMBER for sales representatives based on their assigned sales quota.
SELECT ROW_NUMBER() OVER(ORDER BY SUM(SalesAmountQuota) DESC) AS RowNumber,
FirstName, LastName, CONVERT(varchar(13), SUM(SalesAmountQuota),1) AS SalesQuota FROM dbo.DimEmployee AS e INNER JOIN dbo.FactSalesQuota AS sq ON e.EmployeeKey = sq.EmployeeKey
WHERE e.SalesPersonFlag = 1 GROUP BY LastName, FirstName; Here is a partial result set.
RowNumber FirstName LastName SalesQuota
--------- --------- ------------------ -------------
1 Jillian Carson 12,198,000.00
2 Linda Mitchell 11,786,000.00
3 Michael Blythe 11,162,000.00
4 Jae Pak 10,514,000.00
Answer: A
Explanation:
References:
https://docs.microsoft.com/en-us/sql/t-sql/functions/row-number-transact-sql
https://docs.microsoft.com/en-us/sql/t-sql/queries/select-over-clause-transact-sql

QUESTION NO: 4
Your database contains a table named Purchases. The table includes a DATETIME column named PurchaseTime that stores the date and time each purchase is made. There is a non-clustered index on the PurchaseTime column.
The business team wants a report that displays the total number of purchases made on the current day.
You need to write a query that will return the correct results in the most efficient manner.
Which Transact-SQL query should you use?
A. SELECT COUNT(*)
FROM Purchases
WHERE PurchaseTime = GETDATE()
B. SELECT COUNT(*)
FROM Purchases
WHERE PurchaseTime >= CONVERT(DATE, GETDATE())
AND PurchaseTime < DATEADD(DAY, 1, CONVERT(DATE, GETDATE()))
C. SELECT COUNT(*)
FROM Purchases
WHERE CONVERT(VARCHAR, PurchaseTime, 112) = CONVERT(VARCHAR, GETDATE(), 112)
D. SELECT COUNT(*)
FROM Purchases
WHERE PurchaseTime = CONVERT(DATE, GETDATE())
Answer: B
Explanation:
Two answers will return the correct results (the "WHERE CONVERT..." and "WHERE ... AND ... " answers).
The correct answer for Microsoft would be the answer that is most "efficient". Anybody have a clue as to which is most efficient? In the execution plan, the one that I've selected as the correct answer is the query with the shortest duration. Also, the query answer with "WHERE CONVERT..." threw warnings in the execution plan...something about affecting CardinalityEstimate and SeekPlan.
I also found this article, which leads me to believe that I have the correct answer:
http://technet.microsoft.com/en-us/library/ms181034.aspx

QUESTION NO: 5
You administer a Microsoft SQL Server instance that will support several databases.
You need to ensure that every new database created has a data type named postalcode that contains the same attributes.
What should you do?
A. Create a user-defined data type on the master database.
B. Create a user-defined type on the model database.
C. Create a user-defined type on the master database.
D. Create a user-defined data type on the model database.
Answer: D
Explanation:
One option is to create SQL Server user defined data types.
One trick with new databases is to create the objects in the model database, so as new databases are created the user defined data types will automatically be available.
References: https://www.mssqltips.com/sqlservertip/1628/sql-server-user-defined-data-types-rules- and-defaults/

人によって目標が違いますが、あなたにMicrosoft　Salesforce Customer-Data-Platform試験に順調に合格できるのは我々の共同の目標です。 それで、MicrosoftのSAP P-SAPEA-2023に参加する予定がある人々は速く行動しましょう。 あなたに高品質で、全面的なSalesforce Salesforce-Sales-Representative参考資料を提供することは私たちの責任です。 弊社のチームは開発される問題集はとても全面で、受験生をMicrosoft　Network Appliance NS0-521試験に合格するのを良く助けます。 EXIN PR2F-JPN - 弊社の商品が好きなのは弊社のたのしいです。

Updated: May 28, 2022