それはNewValidDumpsの70-461問題無料問題集です。気楽に試験に合格したければ、はやく試しに来てください。70-461問題無料認定試験に合格することは難しいようですね。 Microsoftの70-461問題無料認定試験は人気があるIT認証に属するもので、野心家としてのIT専門家の念願です。このような受験生は70-461問題無料認定試験で高い点数を取得して、自分の構成ファイルは市場の需要と互換性があるように充分な準備をするのは必要です。 もし不合格になったら、私たちは全額返金することを保証します。

MCSA 70-461 そこで、IT業界で働く人も多くなっています。

弊社の70-461 - Querying Microsoft SQL Server 2012/2014問題無料問題集はあなたにこのチャンスを全面的に与えられます。 最新の70-461 関連日本語版問題集試験問題を知りたい場合、試験に合格したとしてもNewValidDumpsは無料で問題集を更新してあげます。NewValidDumpsの70-461 関連日本語版問題集教材を購入したら、あなたは一年間の無料アップデートサービスを取得しました。

現在IT技術会社に通勤しているあなたは、Microsoftの70-461問題無料試験認定を取得しましたか？70-461問題無料試験認定は給料の増加とジョブのプロモーションに役立ちます。短時間で70-461問題無料試験に一発合格したいなら、我々社のMicrosoftの70-461問題無料資料を参考しましょう。また、70-461問題無料問題集に疑問があると、メールで問い合わせてください。

Microsoft 70-461問題無料 - 弊社の商品が好きなのは弊社のたのしいです。

IT業種の人たちは自分のIT夢を持っているのを信じています。Microsoftの70-461問題無料認定試験に合格することとか、より良い仕事を見つけることとか。NewValidDumpsは君のMicrosoftの70-461問題無料認定試験に合格するという夢を叶えるための存在です。あなたはNewValidDumpsの学習教材を購入した後、私たちは一年間で無料更新サービスを提供することができます。もし試験に不合格になる場合があれば、私たちが全額返金することを保証いたします。

NewValidDumps を選択して１００％の合格率を確保することができて、もし試験に失敗したら、NewValidDumpsが全額で返金いたします。

70-461 PDF DEMO:

QUESTION NO: 1
You administer a Microsoft SQL Server 2012 database named ContosoDb. Tables are defined as shown in the exhibit. (Click the Exhibit button.)
You need to display rows from the Orders table for the Customers row having the CustomerId value set to 1 in the following XML format:
<row OrderId="1" OrderDate="2000-01-01T00:00:00" Amount="3400.00" Name="Customer A"
Country="Australia" />
<row OrderId="2" OrderDate="2001-01-01T00:00:00" Amount="4300.00" Name="Customer A"
Country="Australia" /> Which Transact-SQL query should you use?
A. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML RAW
B. SELECT Name AS 'Customers/Name', Country AS 'Customers/Country', OrderId, OrderDate,
Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId
WHERE Customers.CustomerId = 1 FOR XML PATH ('Customers')
C. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId - Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML AUTO, ELEMENTS
D. SELECT Name, Country, OrderId, OrderDate, Amount
FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML AUTO, ELEMENTS
E. SELECT Name, Country, OrderId, OrderDate, Amount
FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML AUTO
F. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML AUTO
G. SELECT Name AS '@Name', Country AS '@Country', OrderId, OrderDate, Amount FROM Orders
INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML PATH ('Customers')
H. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE
Customers.CustomerId = 1 FOR XML RAW, ELEMENTS
Answer: A

QUESTION NO: 2
Your database contains a table named Purchases. The table includes a DATETIME column named PurchaseTime that stores the date and time each purchase is made. There is a non-clustered index on the PurchaseTime column.
The business team wants a report that displays the total number of purchases made on the current day.
You need to write a query that will return the correct results in the most efficient manner.
Which Transact-SQL query should you use?
A. SELECT COUNT(*)
FROM Purchases
WHERE PurchaseTime = GETDATE()
B. SELECT COUNT(*)
FROM Purchases
WHERE PurchaseTime >= CONVERT(DATE, GETDATE())
AND PurchaseTime < DATEADD(DAY, 1, CONVERT(DATE, GETDATE()))
C. SELECT COUNT(*)
FROM Purchases
WHERE CONVERT(VARCHAR, PurchaseTime, 112) = CONVERT(VARCHAR, GETDATE(), 112)
D. SELECT COUNT(*)
FROM Purchases
WHERE PurchaseTime = CONVERT(DATE, GETDATE())
Answer: B
Explanation:
Two answers will return the correct results (the "WHERE CONVERT..." and "WHERE ... AND ... " answers).
The correct answer for Microsoft would be the answer that is most "efficient". Anybody have a clue as to which is most efficient? In the execution plan, the one that I've selected as the correct answer is the query with the shortest duration. Also, the query answer with "WHERE CONVERT..." threw warnings in the execution plan...something about affecting CardinalityEstimate and SeekPlan.
I also found this article, which leads me to believe that I have the correct answer:
http://technet.microsoft.com/en-us/library/ms181034.aspx

QUESTION NO: 3
You administer a Microsoft SQL Server database that supports a banking transaction management application.
You need to retrieve a list of account holders who live in cities that do not have a branch location.
Which Transact-SQL query or queries should you use? (Each correct answer presents a complete solution. Choose all that apply.)
A. SELECT AccountHolderID
FROM AccountHolder
WHERE CityID <> SOME (SELECT CityID FROM BranchMaster)
B. SELECT AccountHolderID
FROM AccountHolder
WHERE CityID <> ALL (SELECT CityID FROM BranchMaster)
C. SELECT AccountHolderID
FROM AccountHolder
WHERE CityID <> ANY (SELECT CityID FROM BranchMaster)
D. SELECT AccountHolderID
FROM AccountHolder
WHERE CityID NOT IN (SELECT CityID FROM BranchMaster)
Answer: B,D
Explanation:
Verified the answers as correct.

QUESTION NO: 4
You are the administrator for a heavily-used OLTP Microsoft SQL Server database.
You are troubleshooting performance issues seen when using stored procedures in the database. The database stores millions of orders across thousands of customers. Some of the customers have large numbers of orders, while others have only one order. You update the statistics and perform defragmentation of all tables and indexes, but two stored procedures still have issues when accessing data.
p_GetCustomer accepts @companyID as a parameter. From the results of profiling, you know that 90 percent of the calls use the @companyid value of 5, while the other 10 percent of calls are evenly distributed across another 10000 values. While viewing the execution plan, you discover that a non- clustered index seek is used.
p_GetShipDate accepts @orderID as a parameter and returns the ship date for that order. You discover that the execution plan is performing a scan on a non-clustered index that has orderID as the index key.
You need to add appropriate query hints to each stored procedure to improve the performance.
What should you do? To answer, drag the appropriate procedures to the correct hints. Each procedure may be used once, more than once, or not at all. You may need to drag the split bar between panes or scroll to view content.
Answer:
Explanation:
Box 1: Optimize FOR..
OPTIMIZE FOR ( @variable_name { UNKNOWN | = literal_constant } [ , ...n ] ) Instructs the query optimizer to use a particular value for a local variable when the query is compiled and optimized. The value is used only during query optimization, and not during query execution.
Box 2: FORCESEEK
FORCESEEK [ (index_value(index_column_name [ ,... n ] )) ]
Specifies that the query optimizer use only an index seek operation as the access path to the data in the table or view.
References:
https://docs.microsoft.com/en-us/sql/t-sql/queries/hints-transact-sql-query?view=sql-server-2017
https://docs.microsoft.com/en-us/sql/t-sql/queries/hints-transact-sql-table?view=sql-server-2017

QUESTION NO: 5
You use Microsoft SQL Server 2012 database to develop a shopping cart application.
You need to invoke a table-valued function for each row returned by a query.
Which Transact-SQL operator should you use?
A. PIVOT
B. UNPIVOT
C. CROSS APPLY
D. CROSS JOIN
Answer: C
Reference:
http://msdn.microsoft.com/en-us/library/ms175156.aspx

最初の保障はあなたに安心させる高い通過率で、第二の保護手段は、あなたは弊社のソフトを利用してMicrosoftのJuniper JN0-280試験に合格しないなら、我々はあなたのすべての支払を払い戻します。 あなたはインターネットでMicrosoftのISACA CCAK認証試験の練習問題と解答の試用版を無料でダウンロードしてください。 MicrosoftのSalesforce Marketing-Cloud-Advanced-Cross-Channel試験に合格して彼らのよりよい仕事を探せるチャンスは多くなります。 Salesforce Salesforce-AI-Associate - NewValidDumpsはまた一年間に無料なサービスを更新いたします。 NewValidDumpsの提供するMicrosoftのIBM C1000-138試験の資料とソフトは経験が豊富なITエリートに開発されて、何回も更新されています。

Updated: May 28, 2022